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Semmy [17]
3 years ago
8

Whrite thease phusical propartes of acid and base​ please its urgent

Chemistry
1 answer:
AnnyKZ [126]3 years ago
6 0

Explanation:

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Can any one help on this one
enyata [817]
0.004382166 Make sure to round to the right amount of Sig Figs
8 0
3 years ago
WILL GIVE BRAINLIEST
OverLord2011 [107]

Answer:

  • <u><em>butylphenyl ether.</em></u>

Explanation:

The formula of the compound is:

  • CH₃ - CH₂ - CH₂ - CH₂ - O - C₆H₅

1. The functional group is of the kind R - O - R', i.e. two alkyl groups each attached to one end of the oxygen atom. That means that the compound is an ether.

2. One group attached to the oxygen group is CH₃ - CH₂ - CH₂ - CH₂ - which has 4 carbons and is named butyl group.

3. The other group attached to the oxygen atom is C₆H₅ - which is derived from ciclohexane as is known as phenyl group.

4. Using the rule of naming the subtituents in alphabetical order, you name butyl first and phenyl second, so it is <u><em>butylphenyl ether.</em></u>

4 0
3 years ago
If you need an object to move a further distance, how would you adjust the force?
Alborosie

Answer:

slingshot or throw it

Explanation:

4 0
2 years ago
Read 2 more answers
What mass of water is produced from the complete combustion of 4.80×10−3 g of methane?
AnnZ [28]

Answer:Mass of H20 = 0.0108g

Explanation:

The explanation is attached.

3 0
3 years ago
A sample was then prepared containing 14.00 mL of coffee and 8.00 mL of 4.80 ppm Li , and diluted to a 50.00 mL total volume. Th
mafiozo [28]

Answer:

The right answer is "[Na^+]=5.57 \ ppm".

Explanation:

The given values are:

\frac{A_s}{A_{coffee}} =\frac{0.840}{1.000}

According to the question,

The concentration of standard will be:

=  \frac{7.80}{50.00}\times 4.80

=  0.156\times 4.80

=  0.748 \ ppm

Coffee after dilution,

⇒  \frac{A_{coffee}}{C_{coffee}} =F\times \frac{A_s}{C_s}

or,

⇒  C_{coffee}=\frac{A_{coffee}}{A_s}\times \frac{C_s}{F}

On substituting the values, we get

⇒               =\frac{1.000}{0.840}\times \frac{0.748}{1.68}

⇒               =1.191\times 1.3104

⇒               =1.561 \ ppm

hence,

In unknown sample, the concentration of coffee will be:

=  1.561\times \frac{50}{14}

=  \frac{78.05}{14}

=  5.57 \ ppm

7 0
3 years ago
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