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scZoUnD [109]
4 years ago
9

What is the most common climate in Brazil? A, B, C, or, D

Chemistry
1 answer:
Contact [7]4 years ago
4 0

The most common type of climate in Brazil is d. tropical wet and dry.

Brazil is a huge country with many different climates.

However, a large portion of the country has a <em>tropical savanna</em> climate. There are <em>distinct wet and dry seasons</em> and monthly mean temperatures are <em>above 18 °C</em> all year round .

You might be interested in
Help me solve. this is science. Which one is it
Vladimir [108]

Answer:

d is the correct answer i think

7 0
3 years ago
Which trends appear as the elements in Period 3 are considered from left to right?
andreev551 [17]

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

8 0
3 years ago
How many grams of silver nitrate will be needed to produce 8.6 g of silver?
konstantin123 [22]

Answer:

13.5g of AgNO3 will be needed

Explanation:

Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:

<em>Moles Ag-Molar mass: 107.8682g/mol-</em>

8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3

<em>Mass AgNO3 -Molar mass: 169.87g/mol-</em>

0.0797 moles Ag * (169.87g/mol) =

<h3>13.5g of AgNO3 will be needed</h3>

3 0
3 years ago
How many moles of O, will occupy 1.00 L at a temper-
Kay [80]

Moles of O₂ = 3.92

<h3>Further explanation</h3>

Given

V=1 L

T=-118 °C + 273 = 155 K

P = 49.77 atm

Required

moles of O₂

Solution

the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

n= PV/RT

\tt n=\dfrac{49.77~atm\times 1~L}{0.082\times 155}=3.92~moles

7 0
3 years ago
The reaction a(g)⇌b(g) has an equilibrium constant of 5.8 and under certain conditions has q = 336. part a what can you conclude
Vika [28.1K]

Answer:

The answer is "As Q=336, at high-temperature \Delta G_{rxn}>0 and WhenK>1,\Delta G^{\circ}_{rxn}>0."

Explanation:

The equation for the reaction is:

A(g) \leftrightharpoons  B(g)  

K=5.8\\\\Q=336

At equilibrium,

\Delta G^{\circ}_{rxn}>0=-RT \ln \ K

When k=5.8(>1), the value of \ln k would be positive

So, \Delta G^{\circ}_{rxn} is negative (< 0)

So if K > l, \Delta G^{\circ}_{rxn}

If the reaction is not in equilibrium so the equation is :

\Delta G_{rxn}>0=\Delta G^{\circ}_{rxn}+RT \ln Q

Substituting the expression:

\Delta G_{rxn}>0= (-RT \ln K) + RT \ln  Q

                 = RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature \Delta G_{rxn}>0.

5 0
3 years ago
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