Question

A sample of nitrogen gas collected at a pressure of 1.03 atm and a temperature of 279 K is found to occupy a volume of 568 milliliters. How many moles of N2 gas are in the sample

Answer 1

Answer: 0.025 moles of nitrogen gas are there in the sample.

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1.03 atm

V = Volume of gas = 568 ml = 0.568 L   (1L=1000ml)

n = number of moles  = ?

R = gas constant =$0.0821Latm/Kmol$

T =temperature =$279K$

$n=\frac{PV}{RT}$

$n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles$

0.025 moles of nitrogen gas are there in the sample.