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prohojiy [21]
3 years ago
10

A sample of nitrogen gas collected at a pressure of 1.03 atm and a temperature of 279 K is found to occupy a volume of 568 milli

liters. How many moles of N2 gas are in the sample
Chemistry
1 answer:
DIA [1.3K]3 years ago
4 0

Answer: 0.025 moles of nitrogen gas are there in the sample.

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1.03 atm

V = Volume of gas = 568 ml = 0.568 L   (1L=1000ml)

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =279K

n=\frac{PV}{RT}

n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles

0.025 moles of nitrogen gas are there in the sample.

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A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
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Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

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Temperature T=298K

Volume V=11.1

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Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

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 M_f=38.8\%

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3 years ago
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Explanation:

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In which groups of the modern periodic table are very active metals and very active non-metals placed?​
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Explanation:

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