Answer:
provide 180 mm spacing
Explanation:
GIVEN DATA
rectangular beam: (b) = 300 mm, (d) = 575 mm
reinforced for flexure = 4Ф32 bars
WD = 30 kN /m, WL = 45 kN/m
Wu = 1.4 * 30 + 1.6 * 45 = 114 kN/m
i) concrete shear stress ( vc)
100 Ac / bd = (100 * u * 
* 32^2) / 300 * 575 = 1.865
from table 3.8
when: 100 Ac / bd = 1.865 then Vc = 0.778 N/mm^2
Ultimate shear force = (114 *5.5) / 2 = 313.5 kN
design shear stress = V / bd = (313.5 * 10^3) / (300 * 575) = 1.82 N/mm^2
v < 0.8
= 1.82 < 3.75
design link provided according to
Asv / sv = b(v-vc) / 0.87 fy = 300(1.82 - 0.778) / 0.87 (420)
ASv / Sv = 0.855
From table 3.13 :the value of Asv / sv can be calculated as
x = (-25) [ 0.625] + 200 = 184.375 mm
provide 180 mm spacing
Explanation:
1. A sequence of instructions is stored in memory.
2. The memory address wherever the first instruction is found is copied to the instruction pointer.
3. The CPU sends the address within the instruction pointer to memory on the address bus.
4. The CPU sends a “read” signal to the control bus.
5. Memory responds by sending a copy of the state of the bits at that memory location on the
data bus, that the CPU then copies into its instruction register.
6. The instruction pointer is automatically incremented to contain the address of the next
instruction in memory.
7. The CPU executes the instruction within the instruction register.
8. Go to step 3
Steps 3, 4, and 5 are called an instruction fetch. Notice that steps 3 – 8 constitute a cycle, the instruction execution cycle. It is shown graphically below.
A DMA controller can generate memory addresses and initiate memory read or write cycles. It contains several hardware registers that can be written and read by the CPU. These include a memory address register, a byte count register, and one or more control registers.
Answer:
Time of submersion in years = 7.71 years
Explanation:
Area of plate (A)= 16in²
Mass corroded away = Weight Loss (W) = 3.2 kg = 3.2 x 106
Corrosion Penetration Rate (CPR) = 200mpy
Density of steel (D) = 7.9g/cm³
Constant = 534
The expression for the corrosion penetration rate is
Corrosion Penetration Rate = Constant x Total Weight Loss/Time taken for Weight Loss x Exposed Surface Area x Density of the Metal
Re- arrange the equation for time taken
T = k x W/ A x CPR x D
T = (534 x 3.2 x 106)/(16 x 7.9 x 200)
T = 67594.93 hours
Convert hours into years by
T = 67594.93 x (1year/365 days x 24 hours x 1 day)
T = 7.71 years
