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Misha Larkins [42]
3 years ago
15

Que es resistencia ?

Engineering
1 answer:
IRINA_888 [86]3 years ago
5 0
It is when you don’t give up and you stand for your rights
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Two identical billiard balls can move freely on a horizontal table. Ball a has a velocity V0 and hits balls B, which is at rest,
Lyrx [107]

Answer:

Velocity of ball B after impact is 0.6364v_0 and ball A is 0.711v_0

Explanation:

v_0 = Initial velocity of ball A

v_A=v_0\cos45^{\circ}

v_B = Initial velocity of ball B = 0

(v_A)_n' = Final velocity of ball A

v_B' = Final velocity of ball B

e = Coefficient of restitution = 0.8

From the conservation of momentum along the normal we have

mv_A+mv_B=m(v_A)_n'+mv_B'\\\Rightarrow v_0\cos45^{\circ}+0=(v_A)_n'+v_B'\\\Rightarrow (v_A)_n'+v_B'=\dfrac{1}{\sqrt{2}}v_0

Coefficient of restitution is given by

e=\dfrac{v_B'-(v_A)_n'}{v_A-v_B}\\\Rightarrow 0.8=\dfrac{v_B'-(v_A)_n'}{v_0\cos45^{\circ}}\\\Rightarrow v_B'-(v_A)_n'=\dfrac{0.8}{\sqrt{2}}v_0

(v_A)_n'+v_B'=\dfrac{1}{\sqrt{2}}v_0

v_B'-(v_A)_n'=\dfrac{0.8}{\sqrt{2}}v_0

Adding the above two equations we get

2v_B'=\dfrac{1.8}{\sqrt{2}}v_0\\\Rightarrow v_B'=\dfrac{0.9}{\sqrt{2}}v_0

\boldsymbol{\therefore v_B'=0.6364v_0}

(v_A)_n'=\dfrac{1}{\sqrt{2}}v_0-0.6364v_0\\\Rightarrow (v_A)_n'=0.07071v_0

From the conservation of momentum along the plane of contact we have

(v_A)_t'=(v_A)_t=v_0\sin45^{\circ}\\\Rightarrow (v_A)_t'=\dfrac{v_0}{\sqrt{2}}

v_A'=\sqrt{(v_A)_t'^2+(v_A)_n'^2}\\\Rightarrow v_A'=\sqrt{(\dfrac{v_0}{\sqrt{2}})^2+(0.07071v_0)^2}\\\Rightarrow \boldsymbol{v_A'=0.711v_0}

Velocity of ball B after impact is 0.6364v_0 and ball A is 0.711v_0.

5 0
3 years ago
Write a script named dif.py. This script should prompt the user for the names of two text files and compare the contents of the
Ainat [17]

Answer:

1

Created on Nov 3, 2018 @author: ASLand

7import atexit

#Read, nanes of both files

Rrintll"Enter tvo files to be compared below

userliamel input ("Enter the nome of the first file: ")

userliame2 input("Enter the name of the second file: ")

ROpen each file

f1 - open(userNamel, r')

@17 f2 = opan(useriame 2, )

tread all the lines into a list

d1 f1.readlines ()

d2 f2.readlines()

re equivalent, print "Yes" else pri

oiterate, and conpare

#11

the

y

if dl == d2:

print("Yes")

atexit

elif for i in range(@, min(len (d1), len(d2))):

if di[i]!=d2[i]:

PCint("No")

print(d1[i])

pcint(d2[])

7 0
3 years ago
Question 6: Which of the following is NOT true if you are changing into a
baherus [9]

Answer:

You should activate your signals 100 feet before you turn, becuase of that you should not wait until you are turning to turn on your signals. If you do not have working lights use your hands. So the answer that is inccorect is B.

You should activate your signals when you get into the turn lane is <u>NOT true</u>

Because you are supposed to single beforhand not while you're in the lane.

Im taking my drivers ed too. :)

6 0
3 years ago
Describe why the motion of a follower acted on by a cam is periodic motion.
PolarNik [594]
When you go and use a periodic motion there a reason
6 0
2 years ago
A sphere is assumed to have the properties of water and has an initial heat generation 46480 W/m^3 How much should the heat gene
Verdich [7]

Answer:

Resulting heat generation, Q = 77.638 kcal/h

Given:

Initial heat generation of the sphere, Q_{Gi} = 46480 W/m^{3}

Maximum temperature, T_{m} = 360 K

Radius of the sphere, r = 0.1 m

Ambient air temperature, T = 25^{\circ}C = 298 K

Solution:

Now, maximum heat generation, Q_{m} is given by:

T_{m} = \frac{Q_{m}r^{2}}{6K} + T                     (1)

where

K = Thermal conductivity of water at T_{m} = 360 K = 0.67 W/m^{\circ}C

Now, using eqn (1):

360 = \frac{Q_{m}\times 0.1^{2}}{6\times 0.67} + 298

Q_{m} = 24924 W/m^{3}

max. heat generation at maintained max. temperature of 360 K is 24924W/m^{3}

For excess heat generation, Q:

Q = (Q_{Gi} - Q_{m})\times volume of sphere, V

where

V = \frac{4}{3}\pi r^{3}

Q = (46480 - 24924)\times \frac{4}{3}\pi\0.1^{3} = 21556\times \frac{4}{3}\pi\0.1^{3} W/m^{3}

Q = 90.294 W

Now, 1 kcal/h = 1.163 W

Therefore,

Q = \frac{90.294}{1.163} = 77.638 kcal/h

3 0
3 years ago
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