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Sophie [7]
3 years ago
14

A cylinder that is 20 cm tall is filled with water. If a hole is made in the side of the cylinder 5 cm below the top level, how

far will the stream land from the base of the cylinder? Assume that the cylinder is large enough so that the level of the water in the cylinder does not drop significantly.
Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

See description

Explanation:

This is an example where we need Tornicelli's law, which states that the horizontal speed of a fluid that starts falling from an orifice is the same speed that an object acquires from free-falling.

v = \sqrt{2gh}

we are given:

h_{cilinder} = 0.2 [m]\\h = 0.05 [m]\\d=0.15[m]

the horizontal velocity of the water at the start is:

v = \sqrt{2(9.8)(0.05)}=0.989949 [m/s]=1[m/s]

now we need to find the time for the water drops to fall d:

as the gravity is the only force interacting with the water we have:

y(t) = \frac{1}{2} g*t^2

replace for y = d

0.15 = \frac{1}{2} g*t^2=>t=\sqrt{\frac{2*0.15}{9.8}}=0.1749[s]

now that we have t we notice that there are no horizontal forces interacting with the water, so the horizontal position is given by:

x(t)=v*t

Finally, we replace v and t:

x(2.45) = 1*0.1749 = 0.1749 [m]=17.49[cm]

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A solid disk of radius 1.4 cm and mass 430 g is attached by a wire to one of its circular faces. It is twisted through an angle
Neporo4naja [7]

Answer:

    f= 4,186  10²  Hz

Explanation:

El sistema descrito es un pendulo de torsión que oscila con con velocidad angular, que esta dada por

             w = √ k/I

donde ka es constante de torsion de hilo e I es el momento de inercia del disco

El  momento de inercia de indican que giran un eje que pasa                 por enronqueces

           I= ½ M R2  

reduzcamos las cantidades al sistema SI

         R= 1,4 cm = 0,014  m

         M= 430 g = 0,430 kg

substituimos

           w= √ (2 k/M R2)

calculemos  

           w = RA ( 2 370 / (0,430  0,014 2)

           w = 2,963 103 rad/s

la velocidad angular esta relacionada con la frecuencia por

            w =2pi f

            f= w/2π

            f= 2,963 10³/ (2π)

            f= 4,186  10²  Hz

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Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
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Answer:

Explanation:

In a L C R circuit, the average power is given by

P_{av}=V_{rms}I_{rms}Cos\phi

As given in the question

CosФ = R / Z

And we know that

V_{rms}=I_{rms}\times Z

So

P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}

P_{av}=I_{rms}^{2}\times R

6 0
3 years ago
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