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Crank
3 years ago
11

Calculate the energy needed to change 200.0 g of ice from -20.0°C to water at 35.0°C.

Physics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

it's C  24.94KCAL

YOUR WELCOMEEEEEE


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No because you cannot see air so therefore it cannot make shadows

Explanation:

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1 point<br> You throw a ball up in the air with a velocity of 30 m/s. How high does it<br> go?
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Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

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A motorbike accelerates from 15m/s to 25m/s in 15 seconds.
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distance traveled by a uniformly accelerated bike is given as

d = \frac{v_f + v_i}{2} (t)

here we know that

v_f = 25 m/s

v_i = 15 m/s

t = 15 s

now we will have from above equation

d = \frac{15 + 25}{2} (15)

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3 years ago
A mixture of helium and oxygen is used in scuba diving tanks to help prevent ""the bends"". 46 L helium and 12 L oxygen are comb
marin [14]

Answer

given,

For helium

Volume,V = 46 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₁ = ?

number of moles

we know

P V = n R T

n_1 =\dfrac{46 \times 1}{0.0821\times 298}

  n₁ = 1.89 moles

For oxygen

Volume,V = 12 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₂ = ?

number of moles

we know

P V = n R T

n_2 =\dfrac{12 \times 1}{0.0821\times 298}

  n₂ = 0.49 moles

Total volume of tank = 5 L

temperature of tank = 298 K

Partial pressure of helium

P_1=\dfrac{n_1 R T}{V}

P_1=\dfrac{1.89\times 0.0821\times 298}{5}

     P₁ = 9.25 atm

Partial pressure of oxygen

P_2=\dfrac{n_2 R T}{V}

P_2=\dfrac{0.49\times 0.0821\times 298}{5}

    P₂ = 2.39 atm

total pressure

    P = P₁ + P₂

    P = 9.25 + 2.39

    P = 11.64 atm

8 0
3 years ago
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