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galben [10]
3 years ago
11

I will give Brainlyiest! I just need this ASAP :)

Chemistry
1 answer:
serg [7]3 years ago
5 0
Equation of reaction:

                                        2 Na + Cl₂   →   2 NaCl

Oxidation States:
                                         L.H.S                    R.H.S
                      O.N of Na  =  0                           +1  =  O.N of Na in NaCl
                       O.N of Cl  =  0                            -1  =  O.N of Cl in NaCl

Oxidation Reaction:
               In this reaction O.S of Na is changing from 0 to +1 state, means it has oxidized with a loss of 1 electron,

                                             Na   →   Na⁺  +   e⁻

Reduction Reaction:
                In this reaction O.S of Cl is changing from 0 to -1 state, means it has reduced with a gain of 1 electron per atom,

                                            Cl₂  +   2e⁻   →   2Cl⁻

Oxidizing Agent:
                        In this reaction Cl is oxidizing agent as it has gain electron from sodium and has oxidized Na to Na⁺.

Reducing Agent:
                          In this reaction Na is reducing agent as it has given electron to chlorine and has reduced Cl to Cl⁻.
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To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B
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Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of   solvent.

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Molality=\frac{Moles}{\text{Mass of solvent(kg)}}

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

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3 years ago
Ammonia gas will react with oxygen gas to yield nitrogen monoxide gas and water vapor.
ruslelena [56]

Answer:

a) <u>0.168 moles O2</u>

<u>b) </u> <u>9.50 grams O2</u>

<u>c) 0.01662 kg NO</u>

<u>d)</u>88.9 %

Explanation:

Step 1: Data given

Molar mass of NH3 = 17.03 g/mol

Molar mass of O2 = 32 g/mol

Molar mass of NO = 30.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation:

4NH3 + 5O2 → 4NO + 6H2O

a. How many moles of ammonia will react with 6.73g of oxygen?

Calculate moles of oxygen = mass O2/ molar mass O2

moles oxygen =  6.73 grams / 32.00 g/mol = 0.210 moles

Calculate moles of NH3

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.210 moles O2 we need 4/5 *0.210 = <u>0.168 moles O2</u>

<u />

b. If 6.42g of water is produced, how many grams of oxygen gas reacted?

Calculate moles of H2O = 6.42 grams / 18.02 g/mol = 0.356 moles

Calculate moles of O2:

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.356 moles H2O we'll need 5/6 * 0.356 = 0.297 moles O2

Calculate mass of O2 = moles O2 * molar mass O2

Mass O2 = 0.297 moles O2 * 32.00 g/mol =  <u>9.50 grams O2</u>

c. If the reaction uses up 9.43105 g of ammonia, how many kilograms of nitrogen monoxide will be formed?

Calculate moles of ammonia = 9.43105 grams / 17.03 g/mol =0.5538 moles

Calculate moles of NO:

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.5538 moles of NH3 we'll have 0.5538 moles NO

Calculate mass of NO

Mass NO = 0.5538 moles * 30.01 g/mol = 16.62 grams = <u>0.01662 kg NO</u>

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d. When 2.51 g of ammonia react with 3.76 g of oxygen, 2.27 g of water vapor are produced. What is the percentage yield of water?

<em>Calculate moles of NH3</em> = 2.51 grams / 17.03 g/mol = 0.147 moles

<em>Calculate moles of O2 </em>= 3.76 grams / 32 g/mol = 0.118 moles

<em>Determine the limiting reactant</em>

O2 is the limiting reactant, it will completely be consumed (0.118 moles)

NH3 is in excess. There will react 4/5 * 0.118 = 0.0944 moles

There will remain 0.147 - 0.0944 = 0.0526 moles

<em>Calculate moles H2O</em>: For 0.118 moles O2 we'll have 6/5 * 0.118 = 0.1416 moles H2O

<em>Calculate mass H2O</em> = 0.1416 moles * 18.02 g/mol = 2.552 grams H2O

<em>Calculate % yield</em> = (2.27/2.552)*100 % = <u>88.9 %</u>

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Answer:

Explanation:

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