Answer:
26.0g of Ag
Explanation:
Equation of reaction,
Cu + AgNO3 → Ag + CuNO3
We need to find the mass of Ag produced in the reaction by comparing it with the mass of Cu reacting.
From the equation of reaction,
1 mole of Cu reacts with 1 mole of Ag
Number of mole = mass / molarmass
Molar mass of Cu = 63.55g
Molar mass of Ag = 107.87g
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Mass of Cu = 1 × 63.55g
Mass of Cu = 63.55g
Similarly,
Mass of Ag = 1 × 107.87
Mass of Ag = 107.87g.
Now let's go back to the equation of reaction,
1 mole of Cu = 1 mole of Ag;
63.55g of Cu = 107.87g of Ag
15.32g of Cu = x g of Ag
X = (107.87 × 15.32) / 63.55
X = 1652.568 / 63.55
X = 26.00g
26.0g of Ag will be produced when 15.32g of Cu reacts with excess AgNO3
