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4 years ago

Cu + AgNO3 → Ag + CuNO3

Chemistry

1 answer:

tia_tia [17]4 years ago

4 0

Answer:

26.0g of Ag

Explanation:

Equation of reaction,

Cu + AgNO3 → Ag + CuNO3

We need to find the mass of Ag produced in the reaction by comparing it with the mass of Cu reacting.

From the equation of reaction,

1 mole of Cu reacts with 1 mole of Ag

Number of mole = mass / molarmass

Molar mass of Cu = 63.55g

Molar mass of Ag = 107.87g

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of Cu = 1 × 63.55g

Mass of Cu = 63.55g

Similarly,

Mass of Ag = 1 × 107.87

Mass of Ag = 107.87g.

Now let's go back to the equation of reaction,

1 mole of Cu = 1 mole of Ag;

63.55g of Cu = 107.87g of Ag

15.32g of Cu = x g of Ag

X = (107.87 × 15.32) / 63.55

X = 1652.568 / 63.55

X = 26.00g

26.0g of Ag will be produced when 15.32g of Cu reacts with excess AgNO3

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