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Fofino [41]
2 years ago
15

The osmotic pressure of an aqueous solution of ammonium phosphate,

Chemistry
1 answer:
Tems11 [23]2 years ago
5 0

Answer:

the freezeng point of solution is -12°c b/c it dencity is 0.854 formula =

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How did coroners handle their responsibilities in the early 1900s? Why was there a need for significant change in the job?
Lorico [155]

Answer:

In the twentieth century, criminologists and forensics strive to summarize the preceding discoveries. In different countries tendencies are beginning to manifest that increase the field of criminological activity in different branches such as criminalistics in Germany; others, penology; and others like the United States, weighed the study as a whole of the science of crime and the science of social reaction provoked by it. In this century, criminology and forensic science had a notable influence on the evolution of criminal law.

Starting in the mid-20th century, a paradigm shift in forensic criminological science was presented, focusing on the study of three aspects: criminal processes, the social environment, and the victim.

Other factors that were taken into account were biosecurity care, which began to have great relevance and greater care since they began to discover infectious diseases transmitted by cadavers to humans.

Approximately in 1939 it was discovered that anthropometric measurements are values that present similarities between different skeleton patterns.

Explanation:

Legal dentistry also addresses the aspect related to “professions” and people's habits, for example, by 1925 it was already possible to identify a smoker by the coloration that the teeth took and the wear on the incisors and canines where the cigar rested. The morphological characteristics of the teeth were, in many cases, used to identify those they called "degenerates", who were the ones who went outside the guidelines of psychic "normality" of the time; among these were prostitutes, thieves, who according to the author had a considerable volume in the molars, the canines were triangular and long, like the upper central incisors that in some reached 8 mm.

3 0
3 years ago
What is elastic energy? list two examples of where it is found?
Free_Kalibri [48]

Sling shot, Bow and arrow

elastic energy is like a rubber band kind of

8 0
3 years ago
Read 2 more answers
What volume would 0.853 moles of Nitrogen gas occupy at STP?
beks73 [17]

Answer:

19.12 L

Explanation:

At STP(i.e. Standard temperature and pressure).

The volume occupied by one mole of gas = 22.4 L

The pressure = 1 atm

The temperature = 273 K

Thus, since 1 mole of gas = 22.4 L;

Then 0.853 moles of N2 gas will occupy:

= (0.853 moles of N2 gas × 22.4 L)/ 1 mole of N2 gas

= 19.12 L

6 0
3 years ago
Nistu is cooking rice in a pot. When she leaves the pot on the stove for a while, the temperature of the rice increases. What ha
Mila [183]

Answer:

Their average kinetic energy increases

Explanation:

The average kinetic energy of the rice molecules increases as the pot is left on the cooking stove.

Heat is transferred to the pot by conduction from the heat source. The heat is then transferred to the rice in the cooking pot by convection.

  • As the water in the pot heats up.
  • The rice gains thermal energy.
  • This causes the molecules of the rice particles to start vibrating.
  • As the molecules vibrate about their fixed position, their thermal energy continues to increase.
  • Therefore, the amount of heat absorbed by the rice increases with time and this actually cooks the food.
5 0
3 years ago
Read 2 more answers
Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i
ankoles [38]
First, we need to get the value of Ka:

when Ka = Kw / Kb 

we have Kb = 1.8 x 10^-5 

and Kw = 3.99 x 10^-16  so, by substitution:

Ka = (3.99 x 10^-16) /  (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

                 NH4+  + H2O →NH3 +  H+
intial          0.013                       0         0 

change       -X                          +X      +X

Equ        (0.013-X)                      X         X

when Ka = [NH3][H+] / [NH4+] 

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X)  by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]
 
        = -㏒(5.35 x 10^-7)
        = 6.27
6 0
3 years ago
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