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Fofino [41]
2 years ago
15

The osmotic pressure of an aqueous solution of ammonium phosphate,

Chemistry
1 answer:
Tems11 [23]2 years ago
5 0

Answer:

the freezeng point of solution is -12°c b/c it dencity is 0.854 formula =

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A 25.00 mL aliquot of concentrated hydrochloric acid (11.7M) is added to 175.00 mL of 3.25M hydrochloric acid. Determine the num
BlackZzzverrR [31]

Answer:

The number of moles of hydrochloric acid are 0.861

Explanation:

In first solution, the [HCl] is 11.7 M, which it means that 11.7 moles are present in 1 liter.

So we took 25 mL and we have to know how many moles, do we have now.

1000 mL ____ 11.7 moles

25 mL _____ (25 . 11.7)/1000 = 0.2925 moles

This are the moles, we add to the solution where the [HCl] is 3.25 M

In 1000 mL __ we have __ 3.25moles

175 mL ____ we have __ (175 . 3.25)/1000 = 0.56875 moles

Total moles: 0.2925 + 0.56875 = 0.861 moles

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3 years ago
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What particles are affecting by strong nuclear forces?
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proton and neutron

I hope this helps :)

Explanation:

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What volume of hydrogen is necessary to react with 6.25g of nitrogen to produce ammonia?
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Which one of the following is not an agent of chemical weathering?
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