Answer:
n = 0.0814 mol
Explanation:
Given mass, m = 35.7g
The molar mass of Tin(IV) bromate, M = 438.33 g/mol
We need to find the number of moles of bromine. We know that,
No. of moles = given mass/molar mass
So,
So, there are 0.0814 moles of bromine in 35.7g of Tin(IV) bromate.
The question is incomplete, here is the complete question:
The given chemical reaction is:
What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
<u>Answer:</u> The theoretical yield of copper is 44.48 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of aluminium = 12.6 g
Molar mass of aluminium = 27 g/mol
Putting values in equation 1, we get:
The given chemical equation follows:
By Stoichiometry of the reaction:
2 moles of aluminium produces 3 moles of copper
So, 0.467 moles of aluminium will produce = of copper
Now, calculating the mass of copper from equation 1, we get:
Molar mass of copper = 63.5 g/mol
Moles of copper = 0.7005 moles
Putting values in equation 1, we get:
Hence, the theoretical yield of copper is 44.48 grams