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lesantik [10]
2 years ago
15

The sum of 32/4 and 3​

Chemistry
2 answers:
son4ous [18]2 years ago
4 0

Answer:

11

Explanation:

32/4+3=32/4+12/4[taking LCM]

so,32+12/4=44/4

44/4=11

Tju [1.3M]2 years ago
3 0

Answer:

32/4 + 3

8 + 3

= 11

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How many moles of gas sample are 5.0 L container at 373K and 203kPa
Rom4ik [11]
For the purpose we will here use t<span>he ideal gas law:

p</span>×V=n×R×<span>T

V= </span><span>5.0 L

T= </span><span>373K

p= </span><span>203kPa
</span><span>
R is </span> universal gas constant, and its value is 8.314 J/mol×<span>K
</span>
Now when we have all necessary date we can calculate the number of moles:

n=p×V/R×T

n= 203 x 5 / 8.314 x 373 = 0.33 mole
 
6 0
3 years ago
What property can be used to determine if a sample is a pure substance or a mixture?
Yuliya22 [10]

Answer:

Melting point

Explanation:

Pure substances have sharp melting and boiling points while impurities lower the melting point and raise the boiling point

7 0
2 years ago
The mass number of this atom is_________<br><br>​
galben [10]

Answer:

7

Explanation:

The mass number is neutrons plus protons

3 0
2 years ago
If 13.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
Paul [167]

6.349 g mass of anhydrous magnesium sulfate will remain.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 1023 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass MgSO₄.7 H₂O = 246.52 g/mol

Moles =\frac{mass}{molar \;mass}

Moles =\frac{13.0 g}{246.52}

0.0527 moles

Molar mass MgSO₄ = 120.4 g/mol

Mass of anhydrous magnesium sulfate :

( 0.0527 x 120.4 ) => 6.349 g

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

4 0
1 year ago
State the valency of Al in Al²03​
kirill [66]

Answer:

hi

jhy

jj

Explanation:

uythi;ghto

ggh

4 0
3 years ago
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