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3 years ago

Help please use photo

Mathematics

2 answers:

never [62]3 years ago

7 0

Table:
n: 1, 2, 3, 4, 5, 6
f(n): 4, 6, 8, 10, 12, 15

Domain: 1, 2, 3, 4, 5, 6
Range: 4, 6, 8, 10, 12, 15

damaskus [11]3 years ago

4 0

The domain is the input of the function or n in this case. So, in the boxes, you would put [1, 2, 3, 4, 5, 6, ...]

The range is the output of the function or f(n) in this case. So, in the boxes, you would put [4, 6, 8, 10, 12, 14, ...]

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Identify the angle relationship. Which equation can be used to solve for x? (4x + 1) 170

Mice21 [21]

Answer:

680x + 170

Step-by-step explanation:

calculate the product

4 $x$ x170 +170=

680x+ 170

4 0

3 years ago

PLEASE HELP I WILL GIVE 20 POINTS !!!!!!!!!!!!!!!!!!!!!!!!!!

gregori [183]

100 seats
So guessing your supposed to have a even number of each seats that's 100 seats

6 0

3 years ago

What is 2 radical 15 squared

aleksandrvk [35]

$2\sqrt{15^2}=2\cdot15=30\\\\\\2\sqrt{15^2}=2\cdot\left(15^2\right)^\frac{1}{2}=2\cdot15^{2\cdot\frac{1}{2}}=2\cdot15=30$

$\left(2\sqrt{15}\right)^2=2^2\cdot\left(\sqrt{15}\right)^2=4\cdot15=60\\\\\left(2\sqrt{15}\right)^2=2^2\cdot\left(\sqrt{15}\right)^2=4\cdot\left(15^\frac{1}{2}\right)^2=4\cdot15^{\frac{1}{2}\cdot2}=4\cdot15^1=4\cdot15=60$

8 0

3 years ago

The estimated value of the integral from 0 to 2 of x cubed dx , using the trapezoidal rule with 4 trapezoids is

bulgar [2K]

The integral is approximated by the sum,

$\displaystyle\int_0^2f(x)\,\mathrm dx\approx\sum_{n=0}^4\frac12\times\frac{f(x_n)+f(x_{n+1})}2=\frac14\sum_{n=0}^3(f(x_n)+f(x_{n+1}))$

where $f(x)=x^3$ and $x_n=\dfrac12n$ , giving you

$\displaystyle\frac14\sum_{n=0}^3\bigg(\left(\frac n2\right)^3+\left(\frac{n+1}2\right)^3\bigg)$
$\displaystyle\frac1{32}\sum_{n=0}^3(n^3+(n+1)^3)$
$\displaystyle\frac1{32}\sum_{n=0}^3(2n^3+3n^2+3n+1)$

Faulhaber's formulas make short work of computing the sum. You have

$\displaystyle\sum_{n=0}^k1=k+1$
$\displaystyle\sum_{n=0}^kn=\frac{k(k+1)}2$
$\displaystyle\sum_{n=0}^kn^2=\frac{k(k+1)(2k+1)}6$
$\displaystyle\sum_{n=0}^kn^3=\frac{k^2(k+1)^2}4$

which gives

$\displaystyle\frac1{16}\sum_{n=0}^3n^3+\frac3{32}\sum_{n=0}^3n^2+\frac3{32}\sum_{n=0}^3n+\frac1{32}\sum_{n=0}^31$
$\displaystyle\frac{36}{16}+\frac{42}{32}+\frac{18}{32}+\frac4{32}$
$\implies\displaystyle\int_0^2x^3\,\mathrm dx\approx\frac{17}4=4.25$

4 0

3 years ago

Geometry problem I’ll mark the BRAINIEST

melamori03 [73]

Answer:

Step-by-step explanation:

Pretty Tall.

Tan(72) = opposite / adjacent

The opposite is the height of the building

The adjacent = 100

Tan 72 = 3.077

Tan (72) = opposite / 100

3.077 = opposite / 100 Multiply by 100

3.077 * 100 = opposite

opposite = 307.7

opposite rounded = 308

3 0

3 years ago