PH + pOH = 14
12.52 + pOH = 14
pOH = 14 - 12.52
pOH = 1.48
[OH⁻] = 10^ -pOH
[OH⁻] = 10 ^- 1.48
[OH⁻] = 0.033 M
When a molecule can occupy the same active site as the substrate, a situation called enzymes can result.
Answer:
<span>ρ≅13.0⋅g⋅m<span>L<span>−1</span></span></span> = <span>13.0⋅g⋅c<span>m<span>−3</span></span></span>
Explanation:
<span>Density=<span>MassPer unit Volume</span></span> = <span><span>75.0⋅g</span><span><span>(36.5−31.4)</span>⋅mL</span></span> <span>=??g⋅m<span>L<span>−1</span></span></span>
Note that <span>1⋅mL</span> = <span>1⋅c<span>m<span>−3</span></span></span>; these are equivalent units of volume;
i.e. <span>1⋅c<span>m3</span></span> = <span>1×<span><span>(<span>10<span>−2</span></span>⋅m)</span>3</span>=1×<span>10<span>−6</span></span>⋅<span>m3</span>=<span>10<span>−3</span></span>⋅L=1⋅mL</span>.
From the relationship between wavelength and frequency, the frequency of the wave is reduced by half to 60 Hz as the wavelength is increased twice to 10 m at constant speed.
<h3>What is the relationship between wavelength, velocity and frequency of a wave?</h3>
The velocity, frequency and wavelength of a wave are related by the formula given below:
where
- v is velocity
- f is frequency
- λ is wavelength of the wave
From the above relationship:
If the wavelength of a wave is increased to 10m but the speed stays the same at 600 m/s, the frequency can be calculated as follows:
f = v/λ
f = 600/10
f = 60 Hz
Therefore, the frequency of the wave is reduced by half as the wavelength is increased twice at constant speed.
Learn more about frequency and wavelength of a wave at: brainly.com/question/4386945
