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FinnZ [79.3K]
2 years ago
13

In a game of Tug-of-War,

Physics
1 answer:
NemiM [27]2 years ago
8 0
Eventually one of the teams will became tired and its pull will be smaller than that of the other team. When the force acting on the robe are unbalanced the rope will start to move in the direction of the great force.
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Hannah walks 0.30 km to class in 5.0 min. what is her average speed in m/s?
OverLord2011 [107]

Answer:

1.0 m/s

Explanation:

First, convert to SI units.

0.30 km × (1000 m / km) = 300 m

5.0 min × (60 s / min) = 300 s

Speed is distance divided by time:

300 m / 300 s = 1.0 m/s

3 0
3 years ago
The momentum of an object is determined by the object’s mass and velocity. Which object has more momentum?
Gnesinka [82]

Answer:

You need to give the options but the formula is p=mv

Explanation:

7 0
3 years ago
Help!!!!
BARSIC [14]
Can we see the diagram? Thanks.
6 0
3 years ago
How to do this question?​
marissa [1.9K]

Answer:

i3 =11.014A

i5 = 3.15A

Explanation:

Here according to k'chofs first law

i1 =i2 + i3

i3 = i4 + i5

For determine the i1 you have to consider the resultant resistor of the system

4 , 1 and 3 resistors are in pararel

Then, Resultant is

1/4 + 1/1 + 1/3 = 1/ R

R = 12/19

For get total we have to add another remaining 3 resistor because of serious

Then Resultant is = 12/19 + 3

= 69/19

Then using V = IR

40 =i3* 69/19

i3 = 11.014 A

Other 3 resistors are parrarel because of this voltage of those resistors are same.

Then i inversely propotional to its resistor

Then ,

i5 * 2 = (i3-i5)*4/5

i 5 = 3.15 A

7 0
3 years ago
Read 2 more answers
A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / ( g ° C
Sholpan [36]

Answer: 846°C

Explanation:

The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 423 joules

Mass of bismuth = 4.06g

C = 0.123 J/(g°C)

Φ = ?

Then, Q = MCΦ

423 J = 4.06g x 0.123 J/(g°C) x Φ

423 J = 0.5J/°C x Φ

Φ = (423J/ 0.5g°C)

Φ = 846°C

Thus, the change in temperature of the sample is 846°C

4 0
4 years ago
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