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Lapatulllka [165]
3 years ago
10

Most comets have short periods and orbit close to the ecliptic plane. (T/F)

Physics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

False

Explanation:

Most comets are located outside the solar system, in part of the cloud that originated from dust and gas that has remained virtually untouchable for billions of years. The orbit of these comets can reach the order of a light year. Thus, they are called long-period comets.

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A 10-μF capacitor in an LC circuit made entirely of superconducting materials ( R = 0 Ω ) is charged to 100 μC. Then a supercond
satela [25.4K]

Answer:

Vdc=10V

Explanation:

in a closed loop consisting of a super charged capacitor and an inductor, the super charge capacitor acts as a supply when the loop is closed, at t=0, the emf stored in the capacitor is 10V (q/c); and at that same time Vl= voltage across the inductor or loop too would be 10V,

if the loop remains closed for  a longer period, the inductor would absorb energy from the capacitor till it dissipates all charges with itself.

8 0
3 years ago
The water-ice particles forming Saturn's rings are frozen together into a thin sheet that rotates around Saturn like a solid bod
vaieri [72.5K]

Answer:

B. False

Explanation:

According to research by several scientists, Saturn's rings aren't solid, as they appear from Earth.  They are actually made up of floating chunks of water ice, rocks and dust that range in diferent sizes from specks to enormous, even house-sized pieces that orbit Saturn in a ring pattern.

4 0
3 years ago
The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th
worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg

where m_a is the mass of the arrow, m_b is the mass of the block, \Delta H of the change in height of the block after the collision, and v is the velocity of the arrow before it hit the block.

Solving for the velocity v, we get:

$v = \sqrt{\frac{2(m_b+m_a)\Delta Hg}{m_a} } $

and we put in the numerical values

m_a = 0.045kg,

m_b = 1.40kg,

\Delta H = 0.4m,

g= 9.8m/s^2

and simplify to get:

\boxed{ v= 15.9m/s}

The arrow was moving at 15.9 m/s

6 0
3 years ago
A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source
snow_tiger [21]

Answer:

The electrical potential energy is 0.027 Joules.

Explanation:

The values from the question are

charge (q) = 4.5 \times 10^{-5} C

Electric Field strength (E) = 2.0 \times 10^{4} N/C

Distance from source (d) = 0.030 m

Now the formula for the electrical potential energy (U) is given by

U = q \times E \times d

So now insert the values to find the answer

U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

On further solving

U = 0.027 J

8 0
3 years ago
Why does a 10 gram piece if copper take up more space than a 10 gram piece of gold
algol [13]

Answer:

because the mass of the copper is higher than the mass of the gold.

Explanation:

7 0
3 years ago
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