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Vsevolod [243]
3 years ago
8

How would the path of the ball differ on Earth than on the moon?Which statement best compares the accelerations of two objects i

n free fall?
Physics
1 answer:
TEA [102]3 years ago
8 0

Range on earth and height reached is less than on the moon.

accn on moon less than that on earth

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What is the constraint forces
neonofarm [45]

Answer:

(1) Support

(2) Tension

(3) Reaction

The constraint forces are forces that occur in pairs such that the net force (effect) is zero

The details of the constraint forces are;

(1) The support force at the top of the swing acting upwards

(2) The tension in the swing rope acting upwards

(3) The (normal) reaction between the legs of the swing frame and the ground

Explanation:

The normal reaction is the force equal in magnitude and opposite in direction to the total weight force the swing and the person on the swing posses due to gravitational attraction which prevents the downward or sideways motion of the entire swing

6 0
2 years ago
A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this
wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

r=r_o\times A^{\frac{1}{3}}

r_o=1.25 \times 10^{-15} m = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}

r=4.6656\times 10^{-15} m=4.6656 fm

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) F=k\times \frac{q_1q_2}{a^2}

k=9\times 10^9 N m^2/C^2 = Coulombs constant

q_1,q_2 = charges kept at distance 'a' from each other

F = electrostatic force between charges

q_1=+1.602\times 10^{-19} C

q_2=+1.602\times 10^{-19} C

Force of repulsion between two protons on opposite sides of the diameter

a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m

F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}

F=2.6527 N

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

6 0
3 years ago
Rubber is a type of _________.<br> radiator<br> distributor<br> insulator<br> conductor
Talja [164]
C. insulator
Hope this helps ya!
5 0
3 years ago
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A 3,000-N force gives an object an acceleration of 15 m/s^2. The mass of the object is
Bingel [31]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

According to the second Newton's Law,

<em>✔ We have : F = m x a ⇔ m = F/a </em>

  • m = 3000/15
  • m = 200 kg

The mass of the object is therefore 200 kg.

7 0
3 years ago
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A 38.5 kg man is in an elevator
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I’m not too sure but I think it’s 8,91 m/s2
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