Answer:
The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.
Explanation:
4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.
Given that density of the vinegar is same is that of water = 1 g/mL
Mass of the vinegar solution = 100 g
Volume of the vinegar solution = V


V = 100 mL = 0.1 L
Moles of acetic acid =


The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.
The ideal gas equation is pV = nRT
From that you can derive several equations, depending on which variables are fixed.
1) When n and T are fixed:
pV = nRT = constant
pV = constant => p1 V1 = p2 V2 => p1 / V2 = p2 / V1 ---> Boyle's Law
2) When n and V are constant:
p / T = nR/V = constant
p / T = constant => p1 / T1 = p2 / T2 ----> Gay - Lussac's Law
3) when n and p are constant
V / T = nR/p = constant
V / T = constant => V1 / T1 = V2 / T2 ---> Charles' Law
4) When only n is constant
pV / T = nR = constant
pV / T = constant => p1 V1 / T1 = p2 V2 / T2 ----> Combined gas law.
There you have the four equations that agree with the ideal gas law.
The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.
The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.
It can be found using the formula,
m = Z I t
where, m = mass of metal deposited = 75.8g
Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001
I is the current passed
t is the time taken = 75hour = 75 × 60 = 4500s
On subsituting in above formula,
75.8 = E I t / F
⇒ 75.8 = 0.0001 × I × 4500
⇒ I = 168.4 Ampere (A)
Hence, amount of current required to deposit a metal is 168.4A.
Learn more about Law of Equivalence here, brainly.com/question/13104984
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The values for hydroxide ions, hydronium ions and pH are found in the attached picture.
Explanation:
See the attached picture.
Learn more about:
pH
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