Answer:
a. 300 Kg of fertilizer
b. 225 Kg of fertilizer
c. 400 Kg of fertilizer
d. 600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium in a 1 Kg bag of the given fertilizer is 40:15:10.
Therefore a 1 Kg bag contains;
40/100 * 1 Kg = 0.4 Kg of Nitrogen;
15/100 * 1 Kg = 0.15 Kg of phosphorus;
10/100 * 1 Kg = 0.1 Kg of potassium
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at a rate of 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at a rate of 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
Answer:
La constante de equilibrio (K) se expresa como la relación entre las concentraciones molares (mol/l) de reactivos y productos. Su valor en una reacción química depende de la temperatura, por lo que ésta siempre debe especificarse.
Explanation:
Vectors include magnitude & direction so the third option is the correct answer :)
Answer:
41.56 g
Explanation:
Given data:
Mass of NH₄Cl = 15.50 g
Actual yield of AgCl = 35.50 g
Theoretical yield of AgCl = ?
Solution:
Chemical equation:
NH₄Cl + AgNO₃ → AgCl + NH₄NO₃
Number of moles of NH₄Cl:
Number of moles = mass/ molar mass
Number of moles = 15.50 g/ 53.491 g/mol
Number of moles = 0.29 mol
Now we will compare the moles of NH₄Cl with AgCl .
NH₄Cl : AgCl
1 : 1
0.29 : 0.29
Theoretical yield of AgCl:
Mass = number of moles × molar mass
Mass = 0.29 mol ×143.32 g/mol
Mass = 41.56 g
Density = mass/volume
Density = 25 grams/ 125 cm³ = 0.2 g/cm³
