What is conjugate base of nh3? select one:

Diffusion of nonpolar molecules would not be affected by

wariber [46]

+molecule size +steepness of the concentration gradient +temperature + steepness of the electric gradient +steepness

7 0

3 years ago

Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?

sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

$density=\frac{mass}{volume}$

Now, density of isooctane = $0.692 g/mL$

Volume = $3.8 gal$

Since, 1 gallon = 3.78 L

So, 3.8 gal = $3.78 L\times 3.8$

= $14.364 L$

As, 1 L = 1000 mL

Therefore, $14.364 L$ = $14.364 L\times 1000 mL$

Volume in mL = $14364 mL$

Put the values,

$0.692 g/mL=\frac{mass}{14364 mL}$

$m = 0.692 g/mL\times 14364 mL$

= $9939.888 g$

Hence, mass of 3.8 gal of the gasoline is $9939.888 g$ .

6 0

3 years ago

Rank the following from highest to lowest priority according to the Cahn-Ingold-Prelog system: -CH2CH3, -CHCH2, -CCH, -CH3.

mario62 [17]

Answer:

The order will be:

CCH > CHCH₂ > CH₂CH₃> CH₃

Explanation:

According to Cahn-Ingold-Prelog system we rank the groups based on the atomic number of directly attached atom with the chiral carbon.

For example: between C and H, we rank Carbon first.

If the same atoms are attached for different groups then we prioritized based on the second element with highest atomic number.

For example:

Among CH₃ and C₂H₅, the priority will be given to C₂H₅.

If an atom is double or triple bonded to the directly attached atom then each pi bond is considered to be a new atom.

Hence CH=CH₂ means, that there are two carbons attached to CH carbon.

So the order based on above selection rules will be:

CCH > CHCH₂ > CH₂CH₃> CH₃

7 0

4 years ago

The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i

Rus_ich [418]

Answer: a) The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process

a) concentration after 8.8 min:

$8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}$

$\log\frac{0.25}{a-x}=0.15$

$\frac{0.25}{a-x}=1.41$

$(a-x)=0.17M$

b) for concentration to decrease from 0.25M to 0.15M

$t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20$

$t=687s$

7 0

3 years ago

Daniel is conducting an experiment on magnetic objects. He completes more than one trial. Why is it important for Daniel to do t

Luba_88 [7]

Answer:The conclusion is less accurate.

Explanation:

Feb 17, 2021 — He completes more than one trial. Why is it important for Daniel to do this?

4 0

2 years ago