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3 years ago

Determine the electron geometry (eg) and molecular geometry (mg) of CO2.

Chemistry

1 answer:

eimsori [14]3 years ago

6 0

Answer:

eg=linear, mg=linear

Explanation:

First of all, it must be stated that most triatomic molecules are either linear or bent. This depends on the electron geometry of the molecule and the number of bonding groups, multiple bonds and lone pairs present.

CO2 contains four regions of electron density and two bonding groups. For a specie containing two bonding groups, a linear molecular geometry is expected with an angle of 180°.

For a specie having two bonding groups and no lone pairs with multiple bonds, the expected electron geometry is also linear.

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Ammonia, NH3(g), can be used as a substitute for fossil fuels in some internal combustion

sammy [17]

Answer:

4 NH₃ (g) + 3 O₂ (g) ----> 2 N₂ (g) + 6 H₂O (g) + energy

Explanation:

The unbalanced equation:

NH₃ (g) + O₂ (g) ----> N₂ (g) + H₂O (g) + energy

Reactants: 1 nitrogen, 3 hydrogen, 2 oxygen

Products: 2 nitrogen, 2 hydrogen, 1 oxygen

The sort-of balanced equation

2 NH₃ (g) + 1/2 O₂ (g) ----> N₂ (g) + 3 H₂O (g) + energy

I first started by balancing the nitrogens. This then lead me to balance the hydrogens. When I went to balance the oxygens, only a 1/2 coefficient would work. However, 1/2 coefficients are technically incorrect. To get rid of this coefficient, you need to multiply each coefficient by 2.

The balanced equation:

4 NH₃ (g) + 3 O₂ (g) ----> 2 N₂ (g) + 6 H₂O (g) + energy

Reactants: 4 nitrogen, 12 hydrogen, 6 oxygen

Products: 4 nitrogen, 12 hydrogen, 6 oxygen

Now, all of the elements are equal on both sides and there are no 1/2 coefficients. These are the smallest whole-number coefficients because some of the numbers cannot be further simplified (3).

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2 years ago

Does a continental rift form when shear acts on continental crust

asambeis [7]

Yes

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3 years ago

Condensation point AND freezing point of oxygen in C and F?

aliina [53]

Answer:54.36 K (−218.79 °C; −361.82 °F)

Explanation:

7 0

3 years ago

Help I need to show work!

lubasha [3.4K]

Answer:

a. Combustion.

b. $m_C=3.057gC$

c. $m_H=3.67gH$

Explanation:

Hello.

a. In this case, given the reaction by which propane is converted into carbon dioxide and water:

$C_3H_8+5O_2 \rightarrow 3CO_2+4H_2O$

It is known as a combustion reaction since it is about a fuel (here propane) which is burnt by the oxygen contained in the air (21%).

b. Since the carbon dioxide contains all the carbon in the products based on the law of conservation of mass, the yielded grams are computed via a mole mass relationship:

$m_C=11.21gCO_2*\frac{12gC}{44gCO_2}=3.057gC$

Since 44 grams of carbon dioxide contain 12 grams of carbon.

c. As well as b., all the hydrogen is given off in form of water, thus, the required mass turns out:

$m_H=33.0gH_2O*\frac{2gH}{18gH_2O}=3.67gH$

Since 18 grams of water contain 2 grams of hydrogen.

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3 years ago

what is the molarity of a solution prepared by dissolving 1.25g of HCL gas into enough water to make 30cm cube of solution?

Tpy6a [65]

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3 years ago