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Murljashka [212]
1 year ago
7

Given that tan^2 theta=3/8,what is the value of sec theta?

Mathematics
1 answer:
Margaret [11]1 year ago
8 0

Answer:

Sqrt (11/8)

Step-by-step explanation:

Sec^2 - Tan^2 = 1

- Tan^2 = 1 - Sec^2

Tan^2 = -1 + Sec^2

Tan^2 = 3/8

3/8 = -1 + Sec^2 Theta

1 + 3/8 = Sec ^2 Theta

11/8 = Sec^2 Theta

Sqrt ( 11/8) = Sec of theta

-- Gage Millar, Algebra 1/2 Tutor (Pending Pre-Calc Tutor)

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Which value is equivalent to<br> 3/11?<br> OA A. 0.27<br> O<br> B. 0.27<br> OC<br> C. 3.6<br> OD. 3.
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Answer:

0.27 repeating.

Step-by-step explanation:

So to solve this we just have to use division.

1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.

11 goes into 30 2 times, so we have:

0.2

and 30-22=8

So we can add another 0 and make it 80.

Then 11 goes into 80 7 times. So we have:

0.27

and 80-77=3

So again, add the 0, we have 30.

11 goes into 30 2 times, so:

0.272

and 30-22=8

Add another 0 we get 80.

11 goes into 80 7 times.

So finally, we have:

0.2727.

This is a repeating decimal.

This can be shown as:

0.<u>27</u>

So this is your answer!

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Hope this helps!

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2 years ago
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