2. How many grams of NaCl are required to prepare 0.40 L of a 0.75 M solution?
1 answer:
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Answer:
What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?
A) 19.6
B) 39.1
C) 19,600
D) 39,100
E) 276
The correct answer to the question is
B) 39.1 grams
Explanation:
To solve the question
The molarity ratio is given by
188 ml of 0.532 M solution of iodide.
Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles
To find the mass, we note that the Number of moles = from which we have
Mass = Number of moles × molar mass
Where the molar mass of Barium Iodide = 391.136 g/mol
= 0.100016 moles ×391.136 g/mol = 39.12 g
Answer:
1. 2Ca + N → 2CaN
2. 4Li + O → 2Li
O
3. 2KCl + BaF → 2KF + BaCl
4. CH + 2O
→ CO
+ 2H
O
Be sure to balance the number of atoms on both sides of each equation only by adding coefficients to the compounds!!!! Those without a coefficient are meant to have a coefficient of 1.