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KatRina [158]
2 years ago
11

2. How many grams of NaCl are required to prepare 0.40 L of a 0.75 M solution?

Chemistry
1 answer:
Yuri [45]2 years ago
4 0

The mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g. Details about mass can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles of a solution must be initially calculated by using the following formula:

molarity = no of moles ÷ volume

no of moles = 0.75 × 0.40

no of moles = 0.3 moles

mass of NaCl = 0.3 × 58.5 = 17.55g

Therefore, the mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

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108.02cm³

Explanation:

First, rearrange the formula: density = mass/volume so that volume is the subject: volume = mass/density

Next, substitute (plug in) the values:

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Hope this helps!

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The expression for K_c for the given reaction follows:

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