<span>Mass oxigen = 2.81 - 2.50 = 0.31 g
Moles O = 0.31 g / 15.9994 g/mol =0.0194
moles Cu = 2.50 g / 63.546 g/mol =0.0393
we divide by the smallest number
0.0194 / 0.0194 = 1 => O
0.0393 / 0.0194 = 2 => Cu
the formula is Cu2O ( Copper (I) oxide )
Ya got this</span>
Answer:
this can be explained as a non optically active member of a set of stereoisomer, at least two of which are optically active
Explanation:
this means that despite containing two or sterogeonic center the molecules are not chiral
example:
the example above shows at least two choral center and internal mirror plane
Answer:
D. Error is in sentence 1. The beam was a cathode ray.
Explanation:
Legit just looked up his experiments and it said right off the bat he studied cathode rays not gamma.
Elements<span>simplest form of matter that can exist under normal laaboratory conditions</span>
Answer:
The Relative Formula Mass of Fe(NO₃)₂ is 179.8524 grams
Explanation:
The Relative Formula Mass is the mass of one mole of a compound expressed in grams, obtained by adding together the Relative Atomic Masses, RAM, of the elements which makes the compound
The Relative Formula Mass of a compound is the same as its Relative Molecular Mass
The relative formula mass of Fe(NO₃)₂ is given as follows;
The relative atomic mass of Fe = 55.845 amu
The relative atomic mass of nitrogen, N = 14.0067 amu
The relative atomic mass of oxygen, O = 15.999 amu
Therefore, we have;
The formula mass of Fe(NO₃)₂ = (55.845 + 2×(14.0067 + 3×15.999)) amu = 179.8524 amu
The Relative Formula Mass of Fe(NO₃)₂ = 179.8524 grams.
