Answer:
The system has exactly one solution where x = 0 and y = -3.
Step-by-step explanation:
-6x + y = -3
7x - y = 3
(7x - 6x) + (y - y) = 3 - 3
x + 0 = 0
x = 0
7(0) - y = 3
0 - y = 3
-y = 3
y = -3
-6(0) + y = -3
0 + y = -3
y = -3
So, the system has exactly one solution where x = 0 and y = -3.
Hope this helps!
Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
Step-by-step explanation:
Area of square = area of triangle
![side*side = \dfrac{1}{2}b*h\\\\\\x*x=\dfrac{1}{2}*(x+1)(x+2)\\x^{2}=\dfrac{1}{2}[x*x +x*2+1*x+1*2]\\\\\\x^{2}=\dfrac{1}{2}[x^{2}+2x+x+2]\\\\\\x^{2}=\dfrac{1}{2}[x^{2}+3x+2]\\\\\\Multiply \ both \ sides \ by \ 2\\\\2x^{2}=x^{2}+3x+2\\\\2x^{2}-x^{2}-3x-2 = 0](https://tex.z-dn.net/?f=side%2Aside%20%3D%20%5Cdfrac%7B1%7D%7B2%7Db%2Ah%5C%5C%5C%5C%5C%5Cx%2Ax%3D%5Cdfrac%7B1%7D%7B2%7D%2A%28x%2B1%29%28x%2B2%29%5C%5Cx%5E%7B2%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Bx%2Ax%20%2Bx%2A2%2B1%2Ax%2B1%2A2%5D%5C%5C%5C%5C%5C%5Cx%5E%7B2%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Bx%5E%7B2%7D%2B2x%2Bx%2B2%5D%5C%5C%5C%5C%5C%5Cx%5E%7B2%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Bx%5E%7B2%7D%2B3x%2B2%5D%5C%5C%5C%5C%5C%5CMultiply%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%202%5C%5C%5C%5C2x%5E%7B2%7D%3Dx%5E%7B2%7D%2B3x%2B2%5C%5C%5C%5C2x%5E%7B2%7D-x%5E%7B2%7D-3x-2%20%3D%200)
x² - 3x - 2 = 0
Answer:
n= s/180 +2
Step-by-step explanation:
s=(n-2)180
/180
s/180=n-2
+2
s/180 +2 =n
