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IgorC [24]
1 year ago
14

When a source of dim orange light shines on a photosensitive metal, no photoelectrons are ejected from its surface. what could b

e done to increase the likelihood of producing photoelectrons
Physics
1 answer:
padilas [110]1 year ago
5 0

Answer: Replace the orange light source with a higher frequency light source

Explanation:

To expel electrons from a piece of metal, the incoming light must have a minimum frequency to cause a photoelectric effect, i.e., the ejection of photoelectrons from a metal surface, which is also known as the metal's threshold frequency.

If v = frequency of incident photon and vth= threshold frequency, then,

  • For v < vth, there will be no ejection of photoelectron.
  • For v = vth, photoelectrons are just ejected from the metal surface, in this case, the kinetic energy of the electron ejected is zero
  • For v > vth, then photoelectrons will come out of the surface along with kinetic energy

Therefore, we would have to increase the frequency of incident light so that it becomes greater than the threshold frequency of that surface, and consequently a photoelectric process takes place.

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Answer:

3.626 m/s

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12. 7.92/2.2 = 3.6 m/s

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14. 8.96/2.6 = 3.45 m/s

the mean of these numbers is 3.626

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The acceleration of the car at impact is 15m/s².

<h3>What is Newton's Second Law of Motion?</h3>

Newton's second law provides a precise explanation of the modifications that a force can make to a body's motion. According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is equal to the sum of its mass and velocity. Similar to velocity, momentum has both a magnitude and a direction, making it a vector quantity.

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express all the units in their most basic form.

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