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Salsk061 [2.6K]
2 years ago
13

Explain any two factors that affect the pressure at a point inside a liquid​

Physics
2 answers:
ser-zykov [4K]2 years ago
5 0

Answer:

<h3>The depth of that point from the surface. The density of the liquid. Acceleration due to gravity.</h3>

<h2>Mark as brainlest answer ¯\_(☯-☯)_/¯</h2>
vredina [299]2 years ago
4 0
The density of the body and the height or the depth of the body since the formula of liquid pressure is density x height gravity
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A block is at rest on a plank whose angle can be varied. The angle is gradually increased from 0 deg. At 31.8°, the block starts
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Answer:

\mu_s = 0.62

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Explanation:

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x - x_0 = v_0t + \frac{1}{2}at^2\\3.4 = 0 + \frac{1}{2}a(2)^2\\a = 1.7~m/s^2

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F = ma\\F = 1.7m

Now, let’s investigate the free-body diagram of the block.

Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,

F = mg\sin(\theta) - \mu_k mg\cos(\theta)\\1.7m = mg\sin(31.8) - \mu_k mg\cos(31.8)\\1.7 = (9.8)\sin(\theta) - mu_k(9.8)\cos(\theta)\\mu_k = 0.415

As for the static friction, we will consider the angle 31.8, but just before the block starts the move.

mg\sin(31.8) = \mu_s mg\cos(31.8)\\\mu_s = tan(31.8) = 0.62

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