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Salsk061 [2.6K]
2 years ago
13

Explain any two factors that affect the pressure at a point inside a liquid​

Physics
2 answers:
ser-zykov [4K]2 years ago
5 0

Answer:

<h3>The depth of that point from the surface. The density of the liquid. Acceleration due to gravity.</h3>

<h2>Mark as brainlest answer ¯\_(☯-☯)_/¯</h2>
vredina [299]2 years ago
4 0
The density of the body and the height or the depth of the body since the formula of liquid pressure is density x height gravity
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How can you use a ticker tape timer in describing motion graphically?
Bad White [126]
Ticker Tape analysis is a common way of analyzing the motion of the objects to perform in the physics laboratory. A long tape is attached to a moving object and threaded through a device that places a tick upon the tape at regular intervals of time. This ticker tape can also determine if the object is fast or slow. It can also reveal if the object is moving with a constant velocity or accelerating. The changing velocity and acceleration represented by the changing distance between dots in the ticker tape. And also the constant velocity and therefore no acceleration represent the constant distance between dots.

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3 years ago
What is a normal resting heart rate for adults, according to the American
kicyunya [14]
The answer of this question is
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7 0
3 years ago
If the capacity of the lungs of an adult were 3.8 L, how many moles of air would the lungs contain at body temperature and atmos
Ahat [919]

Answer:

  • 0.14955  mol

Explanation:

We can solve this problem using the ideal gas law

P \ V = \ n \ R \ T

where P is the pressure, V the volume, n the number of moles, R the ideal gas constant and T the temperature.

We can use the atmospheric pressure as 1 atm, and the body temperature as 36.5 °C, in Kelvin this is:

T_{body} = 36.5 \° C = (36.5 + 273.15) K = 309.65 \ K

The ideal gas constant is:

R = 0.082057 \frac{L \ atm}{ K \ mol}

taking all this in consideration, the number of moles will be:

n = \frac{P \ V}{  R \ T }

n = \frac{1 \ atm * 3.8 \ L  }{ 0.082057 \frac{L \ atm}{ K \ mol} *  309.65 \ K } [/tex]

n = 0.14955 \ mol

3 0
3 years ago
a body accelerates uniformly from rest at 2m/s^2 for 5 seconds. Calculate its averege velocity in this time​
Lana71 [14]

HERE IS YOUR ANSWER!

8 0
3 years ago
A 0.26 kg rod of length 80 cm is suspended by a frictionless pivot at one end. It is held horizontal and released.
Daniel [21]

Answer:

a) a_{center} = 7.38 ~m/s^2

b) a_{end} = 14.77 ~m/s^2

c) v_{center} = 2.43~m/s

Explanation:

a) Immediately after the rod is released, <u>the rod is still horizontal but now subject to gravity.</u> Since one end of the rod is fixed, then the weight of the rod applies a torque. Then by Newton's Second Law, the acceleration can be found.

\tau =I\alpha

where I is the moment of inertia of the rod with respect to its fixed end, and α is the angular acceleration.

The net torque of the rod is

\vec{\tau} = \vec{r} \times \vec{F}\\\tau = rF\sin(90) = rF

where r is the distance from center of the mass to the fixed end, so r = 0.4 m.

The weight of the rod is w = mg = 0.26 x 9.8 = 2.54 N.

So the net torque is τ = 1.01 Nm.

The moment of inertia of the rod is

I = \frac{1}{3}mL^2 = \frac{1}{3}(0.26)(0.8)^2 = 0.055~kg m^2

So, the Newton's Second Law yields

\tau = I\alpha\\\alpha = \frac{\tau}{I} = \frac{1.01}{0.055} = 18.47

<u>The relation between angular acceleration and linear acceleration is a = αr </u>

So, the linear acceleration of the rod is

a = \alpha r = 7.38~m/s^2

b) Using the same relationship between angular acceleration and linear acceleration, the linear acceleration of the end of the rod can be found.

a = \alpha L = 14.77~m/s^2

c) The conservation of energy can be used to find the velocity when the rod is vertical.

K_1 + U_1 = K_2 + U_2\\0 + mg(L/2) = \frac{1}{2}I\omega^2 + 0\\(0.26)(9.8)(0.4) = \frac{1}{2}(0.055)\omega^2\\\omega = 6.08~rad/s

The linear velocity is v = ωr, so

v = 2.43 m/s.

4 0
3 years ago
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