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Rzqust [24]
3 years ago
6

Which of these is a contact force?

Physics
2 answers:
egoroff_w [7]3 years ago
8 0
The correct answer is B.
Vera_Pavlovna [14]3 years ago
7 0
B is the answer because it causes impact and collides together.
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The rectangular plates in a parallel-plate capacitor are 0.063 m × 5.4 m. A distance of 3.5 × 10–5 m separates the plates. The p
djverab [1.8K]

Answer:

capacitance of the capacitor = 0.18 μ  F

Explanation:

Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²

distance between the plate d = 3.5 × 10–5 m

dielectric value for Teflon K = 2.1

capacitance of capacitor = ?

Formula for capacitance of parallel plate is as follows ,

C= \frac{K\epsilon_0 A}{d} (Where \epsilon_0 = 8.82 \times 10^-12\ \frac{F}{m} )

putting the values in the equation,

C = \frac{2.1\times8.82\times10^-12\times0.3402 }{3.5\times10^-5} =0.18\times 10^-6 =0.18 μ  F

4 0
3 years ago
A 78.5-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 11.3 m/s. With
kirill [66]

Answer:

The man moves across the ice with a speed of 0.345m/s.

Explanation:

From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:

m_mv_m+m_bv_b=0\\\\v_m=-\frac{m_b}{m_m} v_b

Where m_m is the mass of the man, m_b is the mass of the book, and v_m and v_b are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):

v_m=\frac{2.40kg}{78.5kg}(11.3m/s)=0.345m/s

In words, the resulting speed of the man is 0.345m/s.

8 0
3 years ago
Read 2 more answers
a 5.00 kg plane is speeding up on the ground with an applied force of 706 N. If the net force is 450 N, what would be the force
loris [4]

Answer:

The force due to air resistance is 256 N.

Explanation:

Given;

mass of the plane, m = 5 kg

applied force on the plane, Fa = 706 N

the net force on the plane, ∑F= 450 N

Let the force due to air resistance = Fr

The net force on the plane is given as;

Net force = applied force - force due to air resistance

∑F = Fa - Fr

Fr = Fa - ∑F

Fr = 706 - 450

Fr = 256 N.

Therefore, the force due to air resistance is 256 N.

5 0
3 years ago
The magnitude of the magnetic flux through the surface of a circular plate is 5.90 10-5 T · m2 when it is placed in a region of
valkas [14]

Answer:

The strength of the magnetic field is 3.5 x 10⁻³ T

Explanation:

Given;

magnitude of the magnetic flux , Φ = 5.90 x 10⁻⁵ T·m²

angle of inclination of the field, θ = 42.0°

radius of the circular plate, r = 8.50 cm = 0.085 m

Generally magnetic flux in a uniform magnetic field is given as;

Φ = BACosθ

where;

B is the strength of the magnetic field

A is the area of the circular plate

Area of the circular plate:

A = πr²

A = π (0.085)² = 0.0227 m²

The strength of the magnetic field:

B = Φ / ACosθ

B = ( 5.90 x 10⁻⁵) / ( 0.0227 x Cos42)

B = 3.5 x 10⁻³ T

Therefore, the strength of the magnetic field is 3.5 x 10⁻³ T

3 0
3 years ago
3) A dock worker pushes a 72 kg crate up a 2.0 m high,
Vlad [161]

Work done on the crate is 1411.2 J

Explanation:

Work done is defined as the product of force and the distance moved by the object. The unit of work done is in joules and denoted by the symbol J.

                                     Work done = F * d

where F represents the force and d represents the distance moved by the object.

mass = 72 kg , distance moved by the object is given by 2.0 m

Force F = mass * gravity = 72 * 9.8

             = 705.6 N =706 N.

Work done = 706 * 2.0 = 1412 J.

                   

7 0
3 years ago
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