Answer:
a) the values of the angle α is 45.5°
b) the required magnitude of the vertical force, F is 41 lb
Explanation:
Applying the free equilibrium equation along x-direction
from the diagram
we say
∑Fₓ = 0
Pcosα - 425cos30° = 0
525cosα - 368.06 = 0
cosα = 368.06/525
cosα = 0.701
α = cos⁻¹ (0.701)
α = 45.5°
Also Applying the force equation of motion along y-direction
∑Fₓ = ma
Psinα + F + 425sin30° - 600 = (600/32.2)(1.5)
525sin45.5° + F + 212.5 - 600 = 27.95
374.46 + F + 212.5 - 600 = 27.95
F - 13.04 = 27.95
F = 27.95 + 13.04
F = 40.99 ≈ 41 lb
Answer:
1497×10⁵ km
Explanation:
Speed of light in vacuum = 3×10⁵ km/s
Time taken by the light of the Sun to reach the Earth = 8 min and 19 s
Converting to seconds we get
8×60+19 = 499 seconds
Distance = Speed × Time
1 AU = 1497×10⁵ km
The Sun is 1497×10⁵ km from Earth
Answer:
The speed of the roller coaster at this point is 18.74 m/s.
Explanation:
Given that,
Weight of the student, W = 655 kg
Weight of the roller coaster, 
Radius of the roller coaster, r = 18 m
At the bottom of the loop, the weight of the roller coaster us given by :
If m is the mass of the roller coaster,
m = 66.83 kg
So,
v = 18.74 m/s
So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.
Answer:
The solutions found include vortex rings, bounded vortices attached to the sphere and infinite vortex tubes.
Explanation:
