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ladessa [460]
3 years ago
7

By measuring the potential energy of an object relative to the ground, and the object's mass, you can calculate its speed when i

t hits the ground. Explain why you can do this.
A.because gravitational potential energy can convert to elastic potential energy
B.because gravitational potential energy can convert to kinetic energy
C.because the gravitational potential energy can convert to sound energy
D.because gravitational potential energy can convert to electric potential energy
Physics
2 answers:
valentina_108 [34]3 years ago
3 0

Answer:

B.because gravitational potential energy can convert to kinetic energy

Explanation:

You can calculate the speed as it hits the ground because gravitational potential energy can convert to kinetic energy.

In this way, total energy can be conserved.

  • We can equate the kinetic energy and potential energy.
  • From this we can solve for the velocity.
  • This way, we know that the potential energy is changing to kinetic energy.
Oksi-84 [34.3K]3 years ago
3 0

Answer: B

Explanation:

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VikaD [51]

Answer:

a) the values of the angle α is 45.5°

b) the required magnitude of the vertical force, F is 41 lb

Explanation:

Applying the free equilibrium equation along x-direction

from the diagram

we say

∑Fₓ = 0

Pcosα - 425cos30° = 0

525cosα - 368.06 = 0

cosα = 368.06/525

cosα = 0.701

α = cos⁻¹ (0.701)

α = 45.5°

Also Applying the force equation of motion along y-direction

∑Fₓ = ma

Psinα + F + 425sin30° - 600 = (600/32.2)(1.5)

525sin45.5° + F + 212.5 - 600 = 27.95

374.46 + F + 212.5 - 600 = 27.95

F - 13.04 = 27.95

F = 27.95 + 13.04

F = 40.99 ≈ 41 lb

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3 years ago
What would to the earth if it shrinks to 1/3 of a cubic inch. (It is possible)
Eduardwww [97]

Answer:

we would die

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Light travels at a speed of close to 3 x 10^5 km/s in vacuum. Given that it takes light 8 min and 19 s to travel the distance fr
never [62]

Answer:

1497×10⁵ km

Explanation:

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Converting to seconds we get

8×60+19 = 499 seconds

Distance = Speed × Time

\text{Distance}=3\times 10^5\times 499\\\Rightarrow \text{Distance}=1497\times 10^5\ km

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A student has a weight of 655 N. While riding a roller coaster they seem to weigh 1.96x 103 N at the bottom of a dip that has a
Nadya [2.5K]

Answer:

The speed of the roller coaster at this point is 18.74 m/s.

Explanation:

Given that,

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Weight of the roller coaster, F=1.96\times 10^3\ N

Radius of the roller coaster, r = 18 m

At the bottom of the loop, the weight of the roller coaster us given by :

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So,

F=W+\dfrac{mv^2}{r}

v=\sqrt{\dfrac{(F-W)r}{m}}

v=\sqrt{\dfrac{(1.96\times 10^3-655)\times 18}{66.83}}

v = 18.74 m/s

So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.

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