Answer:
Work done = 422.45 kJ
Explanation:
given,
weight of equipment = 6 kN
coefficient of kinetic friction = 0.05
distance up to which it is pulled = 1000 m
constant acceleration = 0.2 m/s²
Work done by the camper = ?
actual acceleration acting a'
m a = m a' - μ mg
a' = a + μ g
a' = 0.2 + 0.05 x 9.8
a' = 0.69 m/s²
Work done = Force x distance
F = m a'
F = 422.44897 N
Work done = F x d
Work done = 422.44897 x 1000
Work done = 422449 J
Work done = 422.45 kJ
Answer:
Angular velocity of merry-go-round is πk - 1 at t= T
Explanation:
From the question it is given that
..........................(1)
since mathematically, angular velocity is defined as
........................(2)
on substituing the value of θ(t) from equation 1 in equation (2) we get
=
............................(3)
on differentiating equation (3) with respect to time we get
ω(t) = πk(1 -) = πk - 1 angular velocity of merry-go-round
Therefore, angular velocity of merry-go-round is πk - 1 at t= T