Answer:110.25 m
Explanation:v^2 = u^2 + 2as
21^2 = 0 - 2*2*s
s = 441/4
s=110.25 m
Answer:
a.0.120mm
b.1.58s
c.0.6329Hz
Explanation:
a. Given that 0.120mm is displaced from equilibrium, 0.120mm after 0.790s on opposite side:
-The amplitude is the maximum displacement from equilibrium.
-The object goes from x=+A to x=-A and back during one cycle.
#Hence, the amplitude of the motion is 0.120mm
b.Motion from maximum positive displacement to maximum negative displacement takes places during half the period of Simple Harmonic Motion(SHM)

#Hence, the period of the motion is 1.58s
c. Frequency is calculated as one divided by the period of the motion.
From b above we know that the motions period is 1.58s
Therefore:
<em>Frequency=1/period=1/1.58=0.6329Hz</em>
<em>#</em><em>The frequency of the motion is </em><em>0.6329Hz</em>
<u>Answer:</u>
<h3>As electric current is carried in a cable, around it, a magnetic field is created. The lines of the magnetic fields form concentric circles around the wire. The direction of the magnetic field hinges on the direction of the current. It can be calculated by pointing the thumb of your right hand in the direction of the moment, using the "right hand law." The position of your curled fingers is in the magnetic field lines. The magnetic field magnitude depends on the sum of current, and the distance from the wire carrying the charge.</h3>
<u></u>
<u>Explanation:</u>
Determine the direction of vector B magnitude B: 

Resultant magnitude strength:
its direction is pointing to the left.
Note: Refer the image attached below
Travis Scott!3&;8284$28&:!;&29395
Answer:
F = 50636.873 N
Explanation:
given,
bucket of water = 700-kg
length of cable = 20 m
Speed = 40 m/s
angle of the cable = 38.0°
let air resistance be = F
tension in rope be = T
T cos 38° = m×g..................(1)
..........(2)
equation (1)/(2)


F = 50636.873 N
Hence the force exerted on the bucket is equal to F = 50636.873 N