Question

I decided to take a trip to the International Space Station (ISS), which is currently orbiting the Earth at an altitude (distance from surface to ISS) of 408 km. When I get to the ISS, I decide to go for a spacewalk outside (disconnected from ISS). Let us say that I have a mass of 60 kg, and the mass of the Earth is 5.97 x 1024 kg. Newton’s gravitational constant G = 6.67 ∗ . The radius (distance from center to surface) of the ∗2 Earth = 6731 km.

Answer 1

The gravitational force I’d experience while I am floating outside the ISS will be 4.47 × 10⁻¹⁵ N.

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

$\rm F=G\frac{mM_E}{R^2} \\\\ \rm F=6.67 \times 10^{-34}\times \frac{60 \times 5.97 \times 10^{24}}{(6731)^2} \\\\ F=4.47 \times 10^{-15} \ N$

Hence, the gravitational force I’d experience while I am floating outside the ISS will be 4.47 × 10⁻¹⁵ N.

To learn more about the gravitational force refer to the link;

brainly.com/question/24783651

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