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-BARSIC- [3]
2 years ago
9

A ball is dropped from the top of a building. it initially moves at 4.0 m/s. after 0.5 seconds, it moves at 3.8 m/s. what force

is responsible for the slowing of the ball? air resistance gravity normal tension
Physics
1 answer:
Dima020 [189]2 years ago
7 0

Air resistance (meeting space requirements)

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One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
Eva8 [605]

Answer:

6666.67 Newtons

Explanation:

The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.

In this case:

  • mass= 0.1mg= 1*10^-7 kg
  • velocity= 4.00*10^3 m/s
  • time= 6.00*10^-8 s

Using velocity and time, acceleration can be calculated as:

  • a= 6.667*10^10 m/s²

Substituting these values into the formula F=ma, the answer is:

  • F= (1*10^-7)kg * (6.667*10^10) m/s²
  • F= 6666.67 Newtons of force
5 0
3 years ago
Select the correct answer. Ben has $10 to spend on dinner. He can have a pizza delivered, drive to a burger place, or go to the
Rudik [331]

Answer:

A. to eat a healthier meal

Explanation:

5 0
4 years ago
An object experiences an acceleration of 9.8 m/s over a distance of 210 m . After that acceleration it has a velocity of 380 m/s
V125BC [204]

374.5m/s

Explanation:

acceleration, a = 9.8m/s²

distance, s = 210m

final velocity, v = 380m/s

unknown:

Initial velocity, u = ?

Solution:

We need to apply one of the equations of motion to solve this problem. The most fitting one is:

   V² = U² + 2as

   U is the unknown:

        U² = V² - 2as

        U² = 380² - 2x 9.8 x 210

        U² =  144,400‬ - 4,116‬ = 140284‬

        U = √140284‬ = 374.5m/s

Learn more:

Motion brainly.com/question/5248528

#learnwithBrainly

7 0
4 years ago
Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t
LiRa [457]

Answer:

The minimum coefficient of friction is 0.544

Solution:

As per the question:

Radius of the curve, R = 48 m

Speed of the car, v = 16 m/s

To calculate the minimum coefficient of static friction:

The centrifugal force on the box is in the outward direction and is given by:

F_{c} = \frac{mv^{2}}{R}  

f_{s} = \mu_{s}mg

where

\mu_{s} = coefficient of static friction

The net force on the box is zero, since, the box is stationary and is given by:

F_{net} = f_{s} - F_{c}  

0 = f_{s} - F_{c}  

\mu_{s}mg = \frac{mv^{2}}{R}  

\mu_{s} = \frac{v^{2}}{gR}  

\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544  

3 0
4 years ago
I’m kinda stuck right now…
kirza4 [7]
This is easy
Number 2 is 20 N to the right
Number 3 is 30 N up
Both are unbalanced
4 0
2 years ago
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