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pshichka [43]
3 years ago
14

Soap bubble interference Light of 690-nm wavelength interferes constructively when reflected from a soap bubble having refractiv

e index 1.33. Determine two possible thicknesses of the soap bubble.
Physics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

The two possible thicknesses of the soap bubble is 129 nm and 389 nm.

Explanation:

Given that,

Wavelength = 690 nm

Refractive index = 1.33

We need to calculate the two possible thicknesses of the soap bubble

Using formula of thickness

t=\dfrac{(m+\dfrac{1}{2})\lambda}{2n}

For m = 0,

Put the value into the formula

t=\dfrac{\dfrac{690\times10^{-9}}{2}}{2\times1.33}

t=129\times10^{-9}\ m

t=129\ nm

For m=1,

Put the value into the formula

t=\dfrac{\dfrac{3\times690\times10^{-9}}{2}}{2\times1.33}

t=389\times10^{-9}\ m

t=389\ nm

Hence, The two possible thicknesses of the soap bubble is 129 nm and 389 nm.

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How does radioactive decay work
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4 years ago
If an electronin an electron beam experiences a downward force of 2.0x10^-14N while traveling in a magnetic field of 8.3x10^-2T
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Answer:

Explanation:

Given that,

Force is downward I.e negative y-axis

F = -2 × 10^-14 •j N

Magnetic field is westward, +x direction

B = 8.3 × 10^-2 •i T

Charge of an electron

q = 1.6 × 10^-19C

Velocity and it direction?

Force in a magnetic field is given as

F = q(V×B)

Angle between V and B is 270, check attachment

The cross product of velocity and magnetic field

F =qVB•Sin270

2 × 10^-14 = 1.6 × 10^-19 × V × 8.3 × 10^-2

Then,

v = 2 × 10^-14 / (1.6 × 10^-19 × 8.3 × 10^-2)

v = 1.51 × 10^6 m/s

Direction of the force

Let x be the direction of v

-F•j = v•x × B•i

From cross product

We know that

i×j = k, j×i = -k

j×k =i, k×j = -i

k×i = j, i×k = -j OR -k×i = -j

Comparing -k×i = -j to given problem

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6 0
3 years ago
The overall energy involved in the formation of CsCl from Cs(s) and Cl2(g) is −443 kJ/mol. Given the following information: heat
german

Answer :  The magnitude of the lattice energy for CsCl is, 667 KJ/mole

Explanation :

The steps involved in the born-Haber cycle for the formation of CsCl :

(1) Conversion of solid calcium into gaseous cesium atoms.

Cs(s)\overset{\Delta H_s}\rightarrow Cs(g)

\Delta H_s = sublimation energy of calcium

(2) Conversion of gaseous cesium atoms into gaseous cesium ions.

Ca(g)\overset{\Delta H_I}\rightarrow Ca^{+1}(g)

\Delta H_I = ionization energy of calcium

(3) Conversion of molecular gaseous chlorine into gaseous chlorine atoms.

Cl_2(g)\overset{\frac{1}{2}\Delta H_D}\rightarrow Cl(g)

\Delta H_D = dissociation energy of chlorine

(4) Conversion of gaseous chlorine atoms into gaseous chlorine ions.

Cl(g)\overset{\Delta H_E}\rightarrow Cl^-(g)

\Delta H_E = electron affinity energy of chlorine

(5) Conversion of gaseous cations and gaseous anion into solid cesium chloride.

Cs^{1+}(g)+Cl^-(g)\overset{\Delta H_L}\rightarrow CsCl(s)

\Delta H_L = lattice energy of calcium chloride

To calculate the overall energy from the born-Haber cycle, the equation used will be:

\Delta H_f^o=\Delta H_s+\Delta H_I+\Delta H_D+\Delta H_E+\Delta H_L

Now put all the given values in this equation, we get:

-443KJ/mole=76KJ/mole+376KJ/mole+121KJ/mole+(-349KJ/mole)+\Delta H_L

\Delta H_L=-667KJ/mole

The negative sign indicates that for exothermic reaction, the lattice energy will be negative.

Therefore, the magnitude of the lattice energy for CsCl is, 667 KJ/mole

5 0
3 years ago
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