Answer: The hydroxide concentration of this sample is 
Explanation:
When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.
The ionic product for water is written as:
![K_w=[H^+]\times [OH^-]](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5Ctimes%20%5BOH%5E-%5D)
![7.7\times 10^{-14}=[H^+]\times [OH^-]](https://tex.z-dn.net/?f=7.7%5Ctimes%2010%5E%7B-14%7D%3D%5BH%5E%2B%5D%5Ctimes%20%5BOH%5E-%5D)
As ![[H^+]=[OH^-]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BOH%5E-%5D)
![2[OH^-]=7.7\times 10^{-14}](https://tex.z-dn.net/?f=2%5BOH%5E-%5D%3D7.7%5Ctimes%2010%5E%7B-14%7D)
![[OH^-]=3.85\times 10^{-7}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D3.85%5Ctimes%2010%5E%7B-7%7D)
Thus hydroxide concentration of this sample is 
Answer:
Explanation:
The answer choices are:
<h2>Solution</h2>
You must use the conversion factors to convert J to kcal.
Dividing both sides by 4.184J:
⇒ 1 = 1cal/4.184J
Dividing both sides by 1,000 cal
⇒ 1 = 1kcal / 1,000 cal
Mutiply<em> 578J</em> by the conversion factors to find <em>kcal</em>:

Notice how the units J and cal cancel to yield kcal at the end.
Answer:
Potential Energy
Explanation:
Right now, the match is giving off no energy to it's environment.
<em>Light</em><em> </em><em>it</em><em>.</em>
Now it's giving off a few kinds:
- Thermal energy (heat)
- Light energy
The match has the potential to have energy, but it currently has none.
A is the answer just did it