Answer:
100 N force have to lift for the board to be carried
Explanation:
Given data
L = 3.00 m
F1 = 60.0 N
w = 160 N
to find out
magnitude F2 of force
solution
we know that F1 and F2 sum is equal to weight of board
so that we can say
F1 + F2 = W
so
F2 = W - F1
put the value W and F1
F2 = 160 - 60
F2 = 100 N
so 100 N force have to lift for the board to be carried
Answer:
D) The objects velocity is zero when its acceleration is a maximum
Explanation:
In a simple harmonic motion, the total energy is the sum of elastic potential energy (U) and kinetic energy (K):
(1)
where
k is the spring constant
x is the displacement
m is the mass
v is the velocity
The total energy E remains constant during the motion, so from the equation (1), we see that:
- At the equilibrium position, the displacement (x) is zero, so the velocity (v) is maximum
- At the point of maximum displacement, the displacement (x) is maximum, while the velocity (v) is zero
Let's also keep in mind that in a simple harmonic motion, the acceleration is directly proportional to the displacement (just the direction is opposite):
So, this means that at the point of maximum displacement, the acceleration is maximum and the velocity is zero.
To solve this problem it is necessary to apply the kinematic equations of movement description, specifically those that allow us to find speed and acceleration as a function of distance and not time.
Mathematically we have to
Where,
Final velocity and Initial velocity
a = Acceleration
x = Displacement
From the description given there is no final speed (since it reaches the maximum point) but there is a required initial speed that is contingent on traveling a certain distance under the effects of gravity
Therefore the speed which must a rock thrown straight up is 14*10^2m/s to reach the edge of our atmosphere.
The displacement and gravity traveled are the same, therefore the final speed will be the same but in the opposite vector direction (towards the earth), that is
Answer:
Option A
Explanation:
By law if conservation of momentum we know that the the initial and final momentum of a system remains conserved . Therefore the final momentum of system will be 400 kg -m/s
<u>Proof</u><u> </u><u>:</u><u>-</u>
Let the final momentum of car be " x " .
By Law of conservation of momentum ,
→ m1 u1 + m2 u2 = m1 v1 + m2 v2
→ 400 kg m/s + 0 = 500 kg - m/s + x
→ x = 400 - 500 kg m/s
→ x = -100 kg - m/s
Combined momentum = -100 + 500 = 400 kg-m/s
_____
<em>*</em><em>*</em><em>Edits</em><em> </em><em>are </em><em>appreciated</em><em>*</em><em>*</em>
Answer:
Q = 6.33μC
Explanation:
To find the value of the charge Q you take into account both gravitational force and electric force over each ball. By symmetry you can use the fact that both balls experiences the same forces. Hence you only take into account the forces for one ball for the x component and y component:
M: mass of the ball = 0.09kg
T: tension of the string
F_e: electric force between charges
angle = 45°
The electric force is given by:
Q: charge of the balls
r: distance between balls = 2m
You divide both equation in order to eliminate the tension T:
By doing Q the subject of the formula and replacing you obtain:
hence, the charge of the balls is 6.33μC