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Artemon [7]
3 years ago
9

_______ are atoms that carry an electric charge.

Physics
2 answers:
Tju [1.3M]3 years ago
5 0
The answer is D. hope this helps.
ioda3 years ago
4 0

Answer:

<u><em>Ions</em></u> are atoms that carry an electric charge.

Explanation:

An ion is an atom or molecule that does not have a neutral electric charge. In other words, ions are atoms or groups of atoms that have an electric charge. Ions with a positive charge are called cations. Those with a negative charge are called anions.

Ionization is the formation of electrically charged molecules or atoms. Atoms are electrically neutral. The loss of one or more electrons from a neutral atom forms a cation. Conversely, an anion is an ion whose net charge is negative due to an increase in the number of electrons.

Cations and anions are usually represented with the symbol of the corresponding atom or group of atoms and the symbol "+" or "-", respectively. If the number of electrons gained or lost is greater than one, this is indicated by the corresponding number.

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KE = (1/2) (mass) (speed)²

KE = (1/2) (20 kg) (40 m/s)²

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Synchronous communications satellites are placed in a circular orbit that is 3.59 107 m above the surface of the earth. What is
suter [353]

Answer: 0.223 m/s^{2}

Explanation:

We can solve this with the Law of Universal Gravitation and knowing the acceleration due gravity g of an object above the surface of the planet decreases with the distance (height) of this object from the center of the planet.

Well, according to the law of universal gravitation:

F=G\frac{m_{E}m}{r^2}  (1)

Where:

F is the module of the force exerted between both bodies

G=6.67(10)^{-11}\frac{m^{3}}{kgs^{2}} is the gravitational constant

m_{E}=5.98(10)^{24} kg is the mass of the Earth

m are the mass of each communications satellite

r=R_{E}+h is the distance between the center of the Earth and the satellite

R_{E}=6.38(10)^{6} m is the radius of the Earth

h=3.59(10)^{7} m is the height of the satellite, measured from the Earth's surface

On the other hand, we know according to <u>Newton's 2nd law of motion:</u>

F=mg  (2)

Combining (1) and (2):

G\frac{m_{E}m}{r^2}=mg  (3)

Isolating g:

g=\frac{G M_{E}}{r^2}  (4)

Remembering r=R_{E}+h:

g=\frac{G M_{E}}{(R_{E}+h)^2}  (5)

g=\frac{(6.67(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24} kg)}{(6.38(10)^{6} m+3.59(10)^{7} m)^2}  

Finally:

g=0.223 m/s^{2}  

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Answer:

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