1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
laiz [17]
1 year ago
15

The decay of a living things allows chemical elements to be lost.

Chemistry
1 answer:
Lelu [443]1 year ago
8 0

Answer: is is true

Explanation:

You might be interested in
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
The law of conservation of mass is applicable to
katrin2010 [14]

Answer:

The law of conservation of mass states that in a closed system, mass is neither created nor destroyed during a chemical or physical reaction. The law of conservation of mass is applied whenever you balance a chemical equation.

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

It is applicable in a chemical when the the mass of the products in a chemical reaction is equal to  the mass of the reactants.

But it is not applicable in a nuclear fusion as some of the mass is generated as energy.

3 0
3 years ago
If you have a heartburn, how you could you safely help the situation
Ket [755]
The answer is:

:Avoid lying down after eating

That should help
7 0
3 years ago
For the reaction 2hbr(g)⇌h2(g)+br2(g), k= 2.00×10−19 at 298 k what can be said about this reaction at this temperature? hints fo
Olin [163]

The equilibrium constant k is actually the ratio of the concentration of the products over the concentration of reactants at equilibrium. So if the concentration of products < concentration of reactants, therefore the constant k will be small. But if the concentration of products > concentration of reactants, the constant k will be large. In this case the value is too small (x10^-19), therefore we can say that the reaction favors the reactant side:

 

the equilibrium lies far to the left

7 0
3 years ago
Why is it important for scientist to be repeatable?
Margarita [4]
It is important for scientists to be repeatable so it lets them see patterns and trends in their results. This is affirmative for their work, making it stronger and better able to support their claims. This helps maintain integrity of data.
3 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the weight of Fe3O4 in 100.0g Fe2O3.
    10·1 answer
  • What type of bonding occurs in zinc(ii) chloride, zncl2?
    7·1 answer
  • What is the partial pressure of oxygen gas in a mixture which contains 540 mmHg He, 203 303 Pa N2 if the total pressure of the m
    9·1 answer
  • The sun rotates on it axis once every:<br><br> 28 hours<br> 120 days<br> 25 days 9 hours
    12·1 answer
  • Which is another word for 10 meters in the metric system?
    13·1 answer
  • The melting point of gallium metal is 29.76⁰C. If a piece of gallium is sliced into three parts, the melting point of each part
    6·1 answer
  • One of the main components of an airbag is the gas that fills it. As part of the design process, you need to determine the exact
    9·2 answers
  • Explain how a lithium ion develops a +1 charge when it loses one electron.​
    6·1 answer
  • What ions are formed when naoh is dissolved in water?.
    5·1 answer
  • The Toucan has a long, narrow beak that allows it to reach fruit that is hard to reach for other birds. Plants, like the Monster
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!