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kow [346]
3 years ago
9

40% of lightbulb produced by shining beauty company have suboptimal performance. 5 bulbs are chosen for test. find the probabili

ty that 2 bulbs or less have suboptimal perfor-mance. (b) 40% of lightbulb produced by shining beauty company have suboptimal performance. 500 bulbs are chosen for test. compute approximately the probability that 210 bulbs or less have suboptimal performance. (c) 0.4% of lightbulb produced by light company have suboptimal performance. 500 bulbs are chosen for test. compute approximately the probability that 2 bulbs or less have subopti-mal performance

Mathematics
1 answer:
omeli [17]3 years ago
4 0
(a) about 68.3%

(b) about 83.1%

(c) about 67.7%

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The probability density function of the time it takes a hematology cell counter to complete a test on a blood sample is f(x)=0.0
uysha [10]

Answer:

a) 20%

b) 40%

c) Mean = 62.5 seconds; Variance = 52.083 seconds

Step-by-step explanation:

The time it takes a hematology cell counter to complete a test on a blood sample is continuously distributed over the period of 50 to 75 seconds with probability f(x) = 0.04.

a) The percentage of tests require more than 70 seconds is:

P(X>70) = 1- \frac{70-50}{75-50} \\P(X>70) =0.2 = 20\%

b)The percentage of tests that require less than one minute (60 seconds) is:

P(X70) =0.4 = 40\%

c) The mean and variance of a continuous distribution are determined by:

M=\frac{A+B}{2}=\frac{50+75}{2}\\ M= 62.5\ seconds\\\\V=\frac{(B-A)^2}{12}=\frac{(75-50)^2}{12}\\  V= 52.083\ seconds

Mean = 62.5 seconds.

Variance = 52.083 seconds.

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3 years ago
How do you write a rule for 2, 10, 5, 250? Order of operations?
Afina-wow [57]

There is no possible answer for this question. Try writing it more clearly.

4 0
3 years ago
A survey showed that 23 out of every 100 students play a musical instrument. What percent of the students surveyed play a musica
Gnom [1K]

Answer:

23%

Step-by-step explanation:

7 0
3 years ago
Holly missed 8 of 185 school days this year. Approximately what percent of school days was Holly in attendance?
natulia [17]
8/185 = 4.3 % 
That is the number of days she missed so she was in attendance

100-4 = 96%
3 0
3 years ago
Read 2 more answers
A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle o
iVinArrow [24]

Answer:

a. 25.98i - 15j mi/h

b. 1.71i + 4.7j mi/h

c. 27.69i -10.3j mi/h

Step-by-step explanation:

a. Identify the ship's vector

Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h

Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h

b. Identify the water current's vector

Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h

Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h

c. Identify the vector representing the ship's actual motion.

The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.

V = v + v'

= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h

= (25.98i + 1.71i + 4.7j - 15j )mi/h

= 27.68i -10.3j mi/h

7 0
3 years ago
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