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2 years ago

Please help with both questions thank you!

Physics

1 answer:

Katen [24]2 years ago

3 0

I think is:

(4)Inner core

(4)different Kingdome different species

hope this help :)

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You happen to know that the coefficient of static friction between your patio table and the ground is 0.42. You decide you want

Deffense [45]

Answer:

If the force applied is larger than 185.2 N, yes.

Explanation:

In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

$F_f = \mu mg$

where

$\mu=0.42$ is the coefficient of static friction

$m=45 kg$ is the mass of the table

$g=9.8 m/s^2$ is the gravitational acceleration

Substituting,

$F_f=(0.42)(45 kg)(9.8 m/s^2)=185.2 N$

So, we are able to move the table if we push with a force larger than 185.2 N.

4 0

2 years ago

Which of the following is the correct relationship among the acceleration, velocity, and position?

Damm [24]

Answer:1

Explanation:

s=displacement

v=velocity of particle

a=acceleration of particle

acceleration can be written as rate of change of velocity

so $a=\frac{\mathrm{d} v}{\mathrm{d} t}$

multiply and divide by $ds$

$a=\frac{\mathrm{d} v}{\mathrm{d} t}\times \frac{ds}{ds}$

$a=\frac{\mathrm{d} v}{\mathrm{d} s}\times \frac{\mathrm{d} s}{\mathrm{d} t}$

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ads=vdv$

option 1 is correct

5 0

2 years ago

Read 2 more answers

Have thick walls<br>Chamaer o the heart<br>which

yulyashka [42]

I don’t get it explain

5 0

2 years ago

The valence of aluminum is +3, and the valence of chlorine is –1. The formula for aluminum chloride is correctly written as A. A

zzz [600]

The correct answer is D actually

7 0

2 years ago

A key falls from a bridge that is 32 m above the water. It falls directly into a model boat, moving with constant velocity, that

FinnZ [79.3K]

Answer:

Speed of the boat, v = 4.31 m/s

Explanation:

Given that,

Height of the bridge, h = 32 m

The model boat is 11 m from the point of impact when the key was released, d = 11 m

Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a = g

$t=\sqrt{\dfrac{2s}{g}}$

$t=\sqrt{\dfrac{2\times 32}{9.8}}$

t = 2.55 seconds

Let v is the speed of the boat. It can be calculated as :

$v=\dfrac{d}{t}$

$v=\dfrac{11\ m}{2.55\ s}$

v = 4.31 m/s

So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.

3 0

2 years ago