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weeeeeb [17]
3 years ago
12

Highway safety engineers want to design roadside barriers that will crumple

Physics
2 answers:
EastWind [94]3 years ago
5 0

Answer:

0.84\:\text{s}

Explanation:

The impulse-momentum theorem states that the impulse on an object (F\Delta t) is equal to the change in momentum of that object (\Delta p).

Set up the following equation:

F\Delta t=\Delta p

Solving for change in momentum:

The momentum of an object is equal to p=mv, where m is the mass of the object and v is the velocity of the object. Since the person's final velocity will be zero, their final momentum will also be zero. Therefore, the person's change in momentum is 68\cdot 27-0=1836\:\text{kgm/s}.

Solving for time:

2180\cdot\Delta t = 1836,\\\Delta t =\frac{1836}{2180},\\\Delta t =\boxed{0.84\:\text{s}}

victus00 [196]3 years ago
3 0

Answer:

If the engineers know that the

If the engineers know that themaximum force that a person can safely withstand is 2180 N, approximately, <u>0</u><u>.</u><u>8</u><u>4</u><u> </u><u>second</u><u> </u>is required to crumple the barrier to safely slow the person

is required to crumple the barrier to safely slow the personwith this force.

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Explain why a ball thrown in space could keep moving forever, while a ball thrown here on Earth will come to a stop.
Dmitriy789 [7]

Answer:

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4 0
2 years ago
An unruly student with a spitwad (a lump of wet paper) of mass 20 g in his pocket finds himself in the school library where ther
jeka94

Answer:

T = 188.5 s, correct is  C

Explanation:

This problem must be worked on using conservation of angular momentum. We define the system as formed by the fan and the paper, as the system is isolated, the moment is conserved

         

initial instant. Before the crash

        L₀ = r m v₀ + I₀ w₀

the angular speed of the fan is zero w₀ = 0

final instant. After the crash

        L_f = I₀ w + m r v

        L₀ = L_f

        m r v₀ = I₀ w + m r v

angular and linear velocity are related

        v = r w

        w = v / r

        m r v₀ = I₀ v / r + m r v

         m r v₀ = (I₀ / r + mr) v

       v = \frac{m}{\frac{I_o}{r}  +mr} \ r v_o

let's calculate

       v = \frac{0.020}{\frac{1.4}{0.6  } + 0.020 \ 0.6  } \ 0.6 \ 4

       v = \frac{0.020}{2.345} \ 2.4

       v = 0.02 m / s

         

To calculate the time of a complete revolution we can use the kinematics relations of uniform motion

        v = x / T

         T = x / v

the distance of a circle with radius r = 0.6 m

         x = 2π r

we substitute

         T = 2π r / v

let's calculate

         T = 2π 0.6/0.02

         T = 188.5 s

reduce

         t = 188.5 s ( 1 min/60 s) = 3.13 min

correct is  C

6 0
3 years ago
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