Answer:
(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is 15.36 A (iv) when 240 volt were disconnected current in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A
Explanation:
Solution
The current drawn by one amp is
I =P/V
I =200/120
I= 1.67 A
(i) The current flow in the black wire is
IBK = 4 * 1.67 A + 1A + 2A
IBK = 9.67 A
(ii) Current flow in the red wire is
IRD = 3 * 1.67 A + 1.67 A + 1A + 2A
= 8.68A + 1 A = 9.68 A
Note: Kindly find an attached copy of part of the solution to the given question above.
Answer: please find the answer in the explanation.
Explanation:
Harmonic can be experienced by any body that repeats itself. The pattern can be sinusoidal, square, tooth etc.
The fundamental differences between the harmonic oscillator dynamics and the simple pendulum dynamics are:
1.) The harmonic oscillator dynamics can be sinusoidal or square wave so far the motion is periodic while the simple pendulum dynamics is always sinusoidal.
2.) In simple pendulum dynamics, the period of oscillation is independent of the amplitude. While the period in harmonic oscillator dynamics depends on the amplitude.
3.) Differential equation is only one method to analyze the simple pendulum dynamics where there are several methods to analyze the harmonic oscillator dynamics.
Answer:

Explanation:
The acceleration of an object is equal to the change in velocity of the object divided by the time taken for the object to change the velocity:

where:
u is the initial velocity
v is the final velocity
t is the time taken for the velocity to change from u to v
For Ms Jackson in this problem, we have:
u = 6 m/s (initial velocity)
v = 0 m/s (final velocity)
t = 4 s (time elapsed)
Substituting into the equation, we find the acceleration:

And the negative sign indicates that the direction of the acceleration is opposite to the direction of motion.
Answer:
the acceleration 
Explanation:
Given that:
the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.
So; the acceleration for the first 6 miles can be calculated by using the formula:
v₂² = v₁² + 2a (Δx)
Making acceleration a the subject of the formula in the above expression ; we have:
v₂² - v₁² = 2a (Δx)




Thus;
Assume the car moves in the +x direction;
the acceleration 