Answer:
hope this helps love! There are three methods of heat transfer: conduction, convection, and radiation. Cooking of food usually uses a combination of these methods. Conduction transfers the heat using direct contact; food is heated directly in a metal pan, in a liquid, or surrounded by air. ... The heat from the water is transferred to the egg.
Explanation:
When the water is heated, thermal expansion happens so the particles move farther apart and then the hot water moves up because it is less dense then the colder water. ... Convection is happening because when air is heated by the fire, the air becomes less dense and moves up because denser things sink.
Answer:
194 V/m
Explanation:
In order to find electric field, we can use the formula of power density
i.e Pd = E^2 / Z
where:
Pd = power density in W/m^2
E = electric field strength in V/m
Z = impedance of free space = 120 * π
E = sqrt(Pd * Z)
-----> re-arranging it for E
before solving, convert Pd unit into W/m^2
Pd= 5mW/cm^2 = 50 W/m^2
Solving for E:
E= sqrt(50 * 120 * π)
E = 137.3 V/m
the above value is RMS value
In order to find the peak amplitude of the oscillating field will therefore be 137.3 * sqrt(2) = 194 V/m
Answer:
The magnitude of the field is 8.384×10^-4 T.
Explanation:
Now, i start solving this question:
First, convert the potential difference(V) 2 kv to 2000 v.
As, we have the final formula is qvB = mv^2/r. It came from the centripetal force and the magnetic force and we know that these two forces are equal. When dealing with centripetal motion use the radius and not the diameter so
r = 0.36/2 = 0.18 m.
As, we are dealing with an electron so we know its mass is 9.11*10^-31 kg and its charge (q) is 1.6*10^-18 C.
We can solve for its electric potential energy by using ΔU = qV and we know potential energy initial is equal to kinetic energy final so ΔU = ΔKE and kinetic energy is equal to 1/2mv^2 J.
qV = 1/2mv^2
(1.6*10^-19C)(2000V) = (1/2)(9.11*10^-31kg) v^2
v = 2.65×10^7 m/s.
These all above steps we have done only for velocity(v) because in the final formula we have 'v' in it. So, now we substitute the all values in that formula and will find out the magnitude of the field:
qvB = mv^2/r
qB = mv/r
B = mv/qr
B = (9.11*10^-31 kg)(2.65×10^7 m/s) / (1.6*10^-19 C)(0.18 m)
Hence, B = 8.384*10^-4 T.
Answer:
HOPE IT HEPLED U !!!!
Explanation:
i think it's (C) They have different units ....
I think the answer may be d I'm not completely sure
