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Degger [83]
2 years ago
11

One acre is equal to 43560ft².How much is it in m²?​

Physics
2 answers:
Goryan [66]2 years ago
4 0

1 ft²= 0.09290304m²

so:

43560ft²= 0.09290304m²×43560

= 4,046.8564224 m²

pychu [463]2 years ago
4 0

Answer: 4046.9m² (approx.)

Explanation:

An acre is 43560 ft², but the US has two feet, the International foot, and the (old) Survey foot. Since 1983, the answer varies by state according to which foot the State has adopted for surveying. (Previously, it was always the Survey foot).

International: 43560 ft² x (0.3048 m/ft)² = 4046.856 422 m²

Survey: 43560 ft² x (1200/3937 m)² = 4046.872 610 m²

Both round to 4046.9 m² if that’s good enough, but there is a tiny difference.

To know more about conversions, refer to:

Reference link - brainly.com/question/1462592

#SPJ2

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One horse is pulling a 755 kg sled straight ahead applying a force of 1988 N. If the acceleration of the sled is 1.36 m/s2, what
Inessa [10]

Answer:

The coefficient of kinetic friction is 0.13

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force on it, the factor of proportionality is the mass. So, we can express that law mathematically as:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

With F the net force, m the mass and a the acceleration of the object. In our case we're interested on what's happening to the sled, then we have to analyze the forces on it, those forces are the weight and the normal force on the vertical direction and the pulling force and frictional force in the horizontal direction. So, because (1) is a vector equation we can express that in their vertical (y) and horizontal (x) components:

F_y=ma_y (2)

F_x=ma_x (3)

On y we have that the acceleration is zero because the sled is not moving upward or downward, remember that the net force on y is the weight (W) pointing downward and the normal force pointing upward:

F_y=W+n=0

Following the convention that positive is upward and negative downward, W=mg=(755)(-9.81):

F_y=(755)(-9.81)+n=0

n=7406.55 N (4)

Now on the x direction we have the sum of the forces is the pulling force (T) and friction force (f)

F_x=F+f=ma_x

Choosing the direction where the horse is pulling F=1988N and the acceleration should be positive too, then:

1988+f=m(1.36)

f=(755)(1.36)-1988=-961.2 N

The negative sign means it's in the opposite direction the horse is pulling

The frictional force is related with the coefficient of kinetic friction in the next way:

|f|=\mu_k n

with μk the coefficient of kinetic friction, and n the normal force that we already found on (4), so we simply solve the last equation for μk:

\mu_k=\frac{|f|}{n}=\frac{961.2}{7406.55}=0.13

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{}                                    Metal A

Least reactive {}           Metal C

(b) (i) Bubbles should form very slowly

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