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2 years ago

9

Four forces of magnitude 10N,15N, 4N, 6N act on on object in the direction North West, East and South respectively, find their m

agnitude and direction of their resultant force?

1 answer:

maria [59]2 years ago

7 0

Magnitude 17 root

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A man in a gym is holding an 8.0-kg weight at arm's length, a distance of 0.55 m from his shoulder joint. What is the torque abo

kipiarov [429]

Answer:

$\tau =37.34\ N m$

Explanation:

given,

mass of the weight = 8 Kg

distance = 0.55 m

angle below horizontal = 30°

torque about shoulder

$\tau = \vec{r} \times \vec{F}$

$\tau = r \times F cos \theta$

$\tau = 0.55 \times 8 \times 9.8 \times cos 30^0$

$\tau =37.34\ N m$

torque about his shoulder join is equal to $\tau =37.34\ N m$

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3 years ago

You pull your little sister across a flat snowy field on a sled. Your sister plus the sled have a mass of 22 kg. The rope is at

kati45 [8]

Answer:

Explanation:

mass of sled, m = 22 kg

Force of pull, F = 31 N

distance move, d = 53 m

Angle between force and distance, θ = 40°

The formula for the work done is

W = F x d x Cos θ

W = 31 x 53 x cos 40

W = 1258.6 J

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2 years ago

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Ulleksa [173]

Explanation:

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2 years ago

Read 2 more answers

Determine the average value of the translational kinetic energy of the molecules of an ideal gas at (a) 27.8°C and (b) 143°C. Wh

Alinara [238K]

Answer:

a) $k_{avg}=6.22\times 10^{-21}$

b) $k_{avg}=8.61\times 10^{-21}$

c) $k_{mol}=3.74\times 10^{3}J/mol$

d) $k_{mol}=5.1\times 10^{3}J/mol$

Explanation:

Average translation kinetic energy ( $k_{avg}$ ) is given as

$k_{avg}=\frac{3}{2}\times kT$ ....................(1)

where,

k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K

T = Temperature in kelvin

a) at T = 27.8° C

or

T = 27.8 + 273 = 300.8 K

substituting the value of temperature in the equation (1)

we have

$k_{avg}=\frac{3}{2}\times 1.38\times 10^{-23}\times 300.8$

$k_{avg}=6.22\times 10^{-21}J$

b) at T = 143° C

or

T = 143 + 273 = 416 K

substituting the value of temperature in the equation (1)

we have

$k_{avg}=\frac{3}{2}\times 1.38\times 10^{-23}\times 416$

$k_{avg}=8.61\times 10^{-21}J$

c ) The translational kinetic energy per mole of an ideal gas is given as:

$k_{mol}=A_{v}\times k_{avg}$

here $A_{v}$ = Avagadro's number; ( 6.02×10²³ )

now at T = 27.8° C

$k_{mol}=6.02\times 10^{23}\times 6.22\times 10^{-21}$

$k_{mol}=3.74\times 10^{3}J/mol$

d) now at T = 143° C

$k_{mol}=6.02\times 10^{23}\times 8.61\times 10^{-21}$

$k_{mol}=5.1\times 10^{3}J/mol$

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2 years ago

A helium balloon has a pressure of 40 psi at 20°C. What will the pressure be at 40°C? Assume constant volume and mass.

Likurg_2 [28]

Answer:

P V = N R T ideal gas equation

P2 / P1 = T2 / T1 where the other variables are constant

P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi

5 0

1 year ago