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liubo4ka [24]
3 years ago
14

PLEASE HELP! what are the steps that occur during the combustion of hydrogen?

Chemistry
1 answer:
Softa [21]3 years ago
5 0

Answer:

Explanation:

Combustion releases energy in a single step in the form of light and heat. Whereas in respiration, energy is released in steps and is stored in the form of ATP.

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Precipitation calculations with Ni2+ and Pb2+
Maurinko [17]

Precipitation calculations with Ni²⁺ and Pb²⁺ a. Use the solubility product for Ni(OH)₂ (s) . the pH at which Ni(OH)₂ begins to precipitate from a 0.18 M Ni²⁺ solution. (Ksp Ni(OH)₂ = 5.5x10⁻¹⁶) is 6.8.

When Ni(OH)₂ starts precipitate :

Ksp of Ni(OH)₂ = [ Ni²⁺ ] [ OH²⁻ ]

5.5x10⁻¹⁶ = [ 0.18 ] [ OH²⁻ ]

[ OH²⁻ ] = 5.5x10⁻¹⁶ / 0.18

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therefore , pH = 14 - 7.2

                  pH = 6.8

Thus, Precipitation calculations with Ni²⁺ and Pb²⁺ a. Use the solubility product for Ni(OH)₂ (s) . the pH at which Ni(OH)₂ begins to precipitate from a 0.18 M Ni²⁺ solution. (Ksp Ni(OH)₂ = 5.5x10⁻¹⁶) is 6.8.

To learn more about pH here

brainly.com/question/15289741

#SPJ1

6 0
1 year ago
8.
devlian [24]
The answer is A because I did this before
8 0
3 years ago
Read 2 more answers
β‑Galactosidase (β‑gal) is a hydrolase enzyme that catalyzes the hydrolysis of β‑galactosides into monosaccharides. A 0.387 g sa
gtnhenbr [62]

Answer:

The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=icRT

where,

\pi = osmotic pressure of the solution = 0.602 mbar = 0.000602 bar

0.000602 bar = 0.000594 atm

(1 atm = 1.01325 bar)

i = Van't hoff factor = 1 (for non-electrolytes)

c = concentration of solute = ?

R = Gas constant = 0.0820\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273.15 +25]=298.15 K

Putting values in above equation, we get:

0.000594 atm=1\times c\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298.15 K\\\\c=2.4278\times 10^{-5} mol/L

The concentration of solute is 2.4278\times 10^{-5} mol/L

Volume of the solution = V =0.137 L

Moles of β‑Galactosidase = n

C=\frac{n}{V(L)}

n=2.4278\times 10^{-5} mol/L\times 0.137 L

n=3.3261\times 10^{-6} mol

To calculate the molecular mass of solute, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of β‑Galactosidase = 3.3261\times 10^{-6} mol

Given mass of β‑Galactosidase= 0.387 g

Putting values in above equation, we get:

3.3261\times 10^{-6} mol =\frac{0.387 g}{\text{Molar mass of solute}}\\\\\text{Molar mass of solute}=116,352.97 g/mol

Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

3 0
3 years ago
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