PLEASE HELPPPPPPPPPPPPP
1 answer:
Empirical formula of the Cyclopropane = C
Molecular formula of the Cyclopropane =
Cyclopropane is a cyclic compound having 3 carbon atoms in a ring.
As we know carbon is having 4 valency, that means it can form 4 bonds with other atoms.
In case of cyclopropane each carbon atom is attached with 2 carbon atoms in a ring, so 2 valency of each carbon atom is used in a ring formation.
The remaining 2 valency are satisfied by hydrogen atoms.
Here, 3 carbons are there so 6 hydrogens are used to satisfy their valency.
An empirical formula is a simple representation of ratio of the atoms present, while a molecular formula is a detailed representation of the total number of atom.
So here, carbon and hydrogen ratio is 1:2 , from this the Empirical formula of the Cyclopropane became C
And the molecular formula of the Cyclopropane is .
Learn more about molecular formula here...
#SPJ10
You might be interested in
Answer:
See explanation below
Explanation:
You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.
Now let's analyze what is happening in the reaction so we can predict the final product.
We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.
Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.
Hope this helps
