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2 years ago

PLEASE HELPPPPPPPPPPPPP

Chemistry

1 answer:

aleksandr82 [10.1K]2 years ago

6 0

Empirical formula of the Cyclopropane = C $H_{2}$

Molecular formula of the Cyclopropane = $C_{3} H_{6}$

Cyclopropane is a cyclic compound having 3 carbon atoms in a ring.

As we know carbon is having 4 valency, that means it can form 4 bonds with other atoms.

In case of cyclopropane each carbon atom is attached with 2 carbon atoms in a ring, so 2 valency of each carbon atom is used in a ring formation.

The remaining 2 valency are satisfied by hydrogen atoms.

Here, 3 carbons are there so 6 hydrogens are used to satisfy their valency.

An empirical formula is a simple representation of ratio of the atoms present, while a molecular formula is a detailed representation of the total number of atom.

So here, carbon and hydrogen ratio is 1:2 , from this the Empirical formula of the Cyclopropane became C $H_{2}$

And the molecular formula of the Cyclopropane is $C_{3} H_{6}$ .

Learn more about molecular formula here...

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4 years ago

a weather balloon is filled with 200L of helium at 27 degree Celsius and 0.950 atm. What would be the volume of the gas at -10 d

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<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

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3 years ago

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Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

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Now put all the given values in the above expression, we get:

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The moles of $H_2SO_4$ is, $6.17\times 10^4mol$

Now we have to calculate the moles of $Na_2CO_3$

The balanced neutralization reaction is:

$Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3$

From the balanced chemical reaction we conclude that,

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4 years ago