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blagie [28]
3 years ago
8

Commercial grade fuming nitric acid contains about 90.0% HNO3 by mass with a density of 1.50 g/mL, calculate the molarity of the

HNO3 solution.
Chemistry
2 answers:
andrew-mc [135]3 years ago
8 0

Answer:

Since molarity is defined as moles of solute per liter of solution, we need to find the number of moles of nitric acid, and the volume of solution.

molar mass of nitric acid (HNO3) = 1 + 14 + (3x16) = 15 + 48 = 63 g/mole

1.50 g/ml x 1000 ml = 1500 g/liter

1500 g/liter x 0.90 = 1350 g/liter of pure HNO3 (the 0.9 is to correct for the fact that it is 90% pure)

1350 g/liter x 1 mole/63 g = 21.43 moles/liter = 21 Molar HNO3

= 21 Molar of HNO3

Delicious77 [7]3 years ago
3 0

Answer:

21.4 M.

Explanation:

Mass of HNO3 = 90%

= 90 g of HNO3 in 100 g of solution.

Density = 1.5 g/ml

Molar mass of HNO3 = 1 + 14 + (3*16)

= 63 g/mol

Number of moles = mass/molar mass

= 90/63

= 1.429 mol.

Volume of solution = mass/density

= 100/1.5

= 66.67 ml of solution.

= 0.0667 l.

Molarity is defined as the number of moles of a substance per unit volume of solution.

Molarity, M = number of moles/volume

= 1.429/0.0667

= 21.4 M.

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Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
Methylamine (ch3nh2) is a weakly basic compound. calculate the kb for methylamine if a 0.253 m solution is 4.07% ionized.
MariettaO [177]
Answer is: Kb for methylamine is 4.37·10⁻⁴.<span>
Chemical reaction: CH</span>₃NH₂ + H₂O → CH₃NH₃⁺ + OH⁻.
c(CH₃NH₂) = 0.253 M.
α = 4.07% ÷ 100% = 0.0407.
[CH₃NH₃⁺] = [OH⁻] = c(CH₃NH₂) · α.
[CH₃NH₃⁺] = [OH⁻] = 0.253 M · 0.0407.
[CH₃NH₃⁺] = [OH⁻] = 0.0103 M.
[CH₃NH₂] = 0.253 M - 0.0103 M.
[CH₃NH₂] = 0.2427 M.
Kb = [CH₃NH₃⁺] · [OH⁻] / [CH₃NH₂]. 
Kb = (0.0103 M)² / 0.2427 M.
Kb = 4.37·10⁻⁴.
8 0
3 years ago
How many significant figures are in the measurement 40, 500 mg? a) two b) three c) four d) five
emmainna [20.7K]
I believe there are 3 significant figures B.
8 0
3 years ago
Complete the sentence. When a base is added to water, hydrogen ions __________.
kobusy [5.1K]

Answer:

Explanation:

Decreases

7 0
2 years ago
Read 2 more answers
15 grams of HCl should theoretically produce 0.42 grams of H2. The reaction actually produced 0.15 grams of H2. What is the perc
Helen [10]

Answer:

35.7%

Explanation:

The percent yield is calculated by the formula:

<em>[(actual yield) / (theoretical yield)] * 100</em>

In this case, the actual yield is 0.15 grams, and the theoretical yield is 0.42 grams. So, putting these values into the equation, we have:

\frac{0.15}{0.42} *100=0.357*100=35.7

Thus, the percent yield of H_2 is 35.7%.

Hope this helps!

8 0
3 years ago
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