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Ostrovityanka [42]
3 years ago
13

50 POINTS!!!

Chemistry
1 answer:
lesya692 [45]3 years ago
7 0

The answer is: K is more reactive than Ca because K has to lose only one electron to complete its outermost shell.

Potassium is a chemical element with atomic number 19 (number of electrons is 19).

Electron configuration of potassium is: ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.

Potassium is the alkali metal and has a single valence electron in the outer electron shell.

Periodic law is the arrangement of the elements in order of increasing atomic number.

For example all alkaline metals (I group of periodic table, Na, K, Cs...) loose one electron in chemical reaction and react vigorously with water.

Reactivity series is an empirical progression of a series of metals, arranged by their reactivity from highest to lowest (alkaline metals have highest reactivity and Noble metals lowest reactivity).

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

Alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons (one electron, earth alkaline metals (right next to alkaline metals) have higher ionization energy than alkaline metals, because they have two valence electrons.


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A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. T
Norma-Jean [14]

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{96.0\ kPa}\times {10.0\ L}={P_2}\times {45.0\ L}

{P_2}=\frac {{96.0}\times {10.0}}{45.0}\ kPa

{P_2}=21.3\ kPa

The final pressure of the gas is:- 21.3 kPa

3 0
3 years ago
A chemist prepares a solution of silver perchlorate by measuring out of silver perchlorate into a volumetric flask and filling t
djverab [1.8K]

Complete Question:

A chemist prepares a solution of silver (I) perchlorate (AgCIO4) by measuring out 134.g of silver (I) perchlorate into a 50.ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the silver (I) perchlorate solution. Round your answer to 2 significant digits.

Answer:

13 mol/L

Explanation:

The concentration in mol/L is the molarity of the solution and indicates how much moles have in 1 L of it. So, the molarity (M) is the number of moles (n) divided by the volume (V) in L:

M = n/V

The number of moles is the mass (m) divided by the molar mass (MM). The molar mass of silver(I) perchlorate is 207.319 g/mol, so:

n = 134/207.319

n = 0.646 mol

So, for a volume of 50 mL (0.05 L), the concentration is:

M = 0.646/0.05

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Answer:

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