The number of landfills would increase because if there are less recycled materials, the more land pollution there will be, and the landfills will be more full and it is a form of pollution.
Answer:
1683.6J
Explanation:
Given:
n= no. Of mol= 2.70 mol
T= Temperature= 30.0 K
Q= n Cv × ∆T .........eqn(1)
Where CV= molar heat capacity=5/2R for diatomic particle ,such as H2
CV= molar heat capacity=3/2R for diatomic, such as H
R= gas constant= 8.314 J/mol.K
Q= heat energy
For a diatomic molecules
Q= n Cv × T
But
Cv= molar heat capacity=5/2R = 5/2(8.314)=20.785
CV= 20.785
. ∆T= Temperature= 30.0 K
Then substitute the values into the eqn(1)
Q= 2.70 × 5/2(8.314) × 30
Q= 2.70 × 20.785 × 30
=1683.6J
Mole=mass/molecular mass (Mr)
mole=volume/ 22.4
Molecular amount: Mole=amount atoms/ Avogadro's number
Concentration: mole=volume x M
The entropy of the given reactions increases (S° > 0):
- 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
- NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.
<h3>What is entropy?</h3>
Entropy measure how disordered a system is. It a measure of how dispersed or random the total energy of a system is. The symbol for entropy is S.
A system in which entropy increases is one in which S° > 0.
The entropy of a system decreases when S° < 0.
Entropy of a system increases (S° > 0) if any change results in an increase in temperature, increase in number of molecules, or an increase in volume.
Considering the given systems, the entropy changes is as follows:
- 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
- 2CO2(g) + N2(g) ---->2CO(g) + 2NO(g) --> no change
- 2N2(g) + O2(g) -----> 2N2O(g) ---> decreases
- S (s,rhombic) + 2CO(g) ----> SO2(g) + 2C (s,graphite) ---> no change
- NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.
In conclusion, an increase in volume and moles of substances results in entropy increase.
Learn more about entropy at: brainly.com/question/26691503
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