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monitta
2 years ago
12

wood is a better insulator than glass so why is fiberglass commonly used as an insulator in wooden buildings why?

Physics
2 answers:
german2 years ago
5 0

Answer:

So that it may trap the solar radiations and maintain the temperature of the wooden building.

Explanation:

Wood is not as effective an insulator as fiberglass. It comes in a number of widths, the widest being 3/4 inch, which has an R-value of 0.94. However, fiberglass, the thinnest of which is 3/4 inch, has an R-value of 3. Therefore, fiberglass is a better insulator.

miss Akunina [59]2 years ago
3 0

Air is an excellent insulator. Fiberglass is a good insulator because of the vast amount of air spaces trapped in it. Therefore fiberglasses are used as insulator in wooden buildings than any other insulator.

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4) (5 points) Given are the magnitudes and orientations (with respect to x-axis) of 3
Kazeer [188]

Expand each vector into their component forms:

\vec A=(4.5\,\mathrm N)(\cos\theta_A\,\vec\imath+\sin\theta_A\,\vec\jmath)=(2.58\,\vec\imath+3.69\,\vec\jmath)\,\mathrm N

Similarly,

\vec B=(-1.23\,\vec\imath+0.860\,\vec\jmath)\,\mathrm N

\vec C=(-3.44\,\vec\imath-4.91\,\vec\jmath)\,\mathrm N

Then assuming the resultant vector \vec R is the sum of these three vectors, we have

\vec R=\vec A+\vec B+\vec C

\vec R=(-2.09\,\vec\imath-0.368\,\vec\jmath)\,\mathrm N

and so \vec R has magnitude

\|\vec R\|=\sqrt{(-2.09)^2+(-0.368)^2}\,\mathrm N\approx2.12\,\mathrm N

and direction \theta_R such that

\tan\theta_R=\dfrac{-0.368}{-2.09}\implies\theta_R=-170^\circ=190^\circ

5 0
3 years ago
Help meh in this question plzzz <br>​
iragen [17]

The Moment of Inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

I = I_{D} - I_{H} (1)

Where:

  • I_{D} - Moment of inertia of the Disk.
  • I_{H} - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right) (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole (m):

\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}

m = \frac{1}{2}\cdot M

And the resulting equation is:

I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)

I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}

I = \frac{15}{32}\cdot M\cdot R^{2}

The moment of inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Please see this question related to Moments of Inertia: brainly.com/question/15246709

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28. Which of the following correctly shows the order of highest amount of friction to the lowest amount of
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Answer:

\mathrm{d.\:Static,\: Sliding,\:Rolling}

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Static friction occurs when an object initially starts at rest. When the surfaces of the materials touch, the microscopic unevenness interlock greatest with each other, causing the most friction out of the three.

During sliding friction, an object is already moving or in motion. The microscopic surfaces still interlock, but because the object is in motion, it has a momentum. Therefore, the magnitude of sliding friction is less than that of static friction.

Rolling friction occurs when an object rolls across some surface. Rather than surfaces interlocking, rolling friction is caused by the constant distortion of surfaces. As it rolls, the surfaces of the object are constantly wrapping and changing. This distortion causes the rolling friction. However, it is much less in magnitude when compared to static or sliding friction.

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Which of these materials is permeable?​
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Correct answer is letter B. sandstone
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