Answer:
1) R1 + ((R2 × R3)/(R2 + R3))
2) 0.5 A
3) 3.6 V
Explanation:
1) We can see that resistors R2 and R3 are in parallel.
Formula for sum of parallel resistors; 1/Rt = 1/R2 + 1/R3
Making Rt the subject gives;
Rt = (R2 × R3)/(R2 + R3)
Now, Resistor R1 is in series with this sum of R2 and R3. Thus;
Total resistance of circuit = R1 + ((R2 × R3)/(R2 + R3))
2) R_total = R1 + ((R2 × R3)/(R2 + R3))
We are given;
R1 = 7.2 Ω
R2 = 8 Ω
R3 = 12 Ω
R_total = 7.2 + ((8 × 12)/(8 + 12))
R_total = 7.2 + 4.8
R_total = 12 Ω
Formula for current is;
I = V/R
I = 6/12
I = 0.5 A
3) since current through the circuit is 0.5 and R1 is 7.2 Ω.
Thus, potential difference through R1 is;
V = IR = 0.5 × 7.2 = 3.6 V
Answer:
the terminal velocity of 14 nested coffee filters is 3.2 m/s
Explanation:
Given the data in the question;
we know that;
The terminal velocity is proportional to the square root of weight.
v ∝ √W
v = k√W
the proportionality constant depends upon the surface area and the density of the medium (like air). The coffee filters can be stacked such that the resulting area is roughly unchanged. So, the constant of proportionality k is also unchanged
v/√W = constant
v₂/√W₂ = v₁/√W₁
v₂ = v₁√(W₂ / W₁ )
given that;
v₁ = 0.856 m/s,
W₂ = 14W₁; meaning 14 coffee filters have 14 times the weight of a single coffee filter
so we substitute
v₂ = 0.856 √(14W₁ / W₁ )
v₂ = 0.856 √( 14( W₁/W₁)
v₂ = 0.856 √( 14(1)
v₂ = 0.856 √( 14 )
v₂ = 0.856 × 3.741657
v₂ = 3.2 m/s
Therefore, the terminal velocity of 14 nested coffee filters is 3.2 m/s
Answer:
Explanation:
The given time is 1 / 4 of the time period
So Time period of oscillation.
= 4 x .4 =1.6 s
When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum
velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .
So required velocity is the maximum velocity of the block while remaining in contact with the spring.
v ( max ) = w A = 1.32 m /s.
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