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3 years ago

What happens to the force between the spheres when you increase the mass of one of the spheres?

Physics

2 answers:

konstantin123 [22]3 years ago

8 0

Answer: The force between two spheres increase when mass of one or both spheres are increased.

Explanation:

According to universal law of gravitation “every body in the universe attracts every other body with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them”.

It is given by the expression

$F=(GM_1 M_2)/r^2$

Where G is the gravitational constant, $M_1 ,M_2$ are the masses of the bodies and r is the distance between them.

In the question two conditions are given.

Mass of one object is increased

Masses of both objects are increased.

Since force between two objects is directly proportional to the masses, the force increases in both cases.

andrew11 [14]3 years ago

4 0

The force between the spheres increases when the mass increases in one of the spheres.

<u>Explanation:</u>

Newton law of universal gravity extends gravity beyond the earth's surface. This gravity depends directly on the mass of both objects and is inversely proportional to square of distance between their centers.

$\bold{F=\frac{G \times\left(m_{1} \times m_{2}\right)}{\left(r^{2}\right)}}$

Since gravity is directly proportional to “mass of both interacting objects”, stronger objects with greater gravitational force attract. If the mass of one object increases, gravity between them also increases. For example, if an object's mass of one double, force between them also doubles.

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Which statements below are true?

Ilya [14]

The correct statements are that the speed decreases as the distance decreases and speed increases as the distance increases for the same time.

Answer:

Option A and Option B.

Explanation:

Speed is defined as the ratio of distance covered to the time taken to cover that distance. So Speed = Distance/Time. In other words, we can also state that speed is directly proportional to the distance for a constant time. Thus, the speed will be decreasing as there is decrease in distance for the same time. As well as there will be increase in speed as the distance increases for the same time. So option A and option B are the true options. So if there is decrease in the distance due to direct proportionality the speed will also be decreasing. Similarly, if the distance increases, the speed will also be increasing.

7 0

3 years ago

Brandon pushes an object on a ramp as shown in the diagram.

stiks02 [169]

The force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is: B. a frictional force.

<h3>What is a force?</h3>

A force can be defined as a push or pull of an object or physical body, which typically results in a change of motion (acceleration), especially due to the interaction of the object with another.

<h3>The types of force.</h3>

In Science, there are different types of force and these include the following:

Gravitational force

Tension force.

Electrical force

Normal Force.

Magnetic force

Air resistance force

Applied force

Frictional force.

<h3>What is a frictional force?</h3>

Friction force can be defined as a type of force that resists and slows the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, a frictional force prevents two surfaces from easily sliding over or slipping across one another.

In this context, we can infer and logically deduce that the force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is a frictional force.

Read more on frictional force here: brainly.com/question/25253774

#SPJ1

Complete Question:

Brandon pushes an object on a ramp as shown in the diagram.

While Brandon pushes the object and it remains in contact the ramp, which force has the greatest effect on causing it to slow?

A. the applied force

B. a frictional force

C. the force due to gravity

D. a force of air resistance

5 0

2 years ago

A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free e

Serhud [2]

Answer: The electron number density (the number of electrons per unit volume) in the wire is $6.0 \times 10^{28} m^{-3}$ .

Explanation:

Given: Current = 5.0 A

Area = $4.0 \times 10^{-6} m^{2}$

Density = 2.7 $g/cm^{3}$ , Molar mass = 27 g

The electron density is calculated as follows.

$n = \frac{density}{mass per atom}\\= \frac{\rho}{\frac{M}{N_{A}}}\\$

where,

$\rho$ = density

M = molar mass

$N_{A}$ = Avogadro's number

Substitute the values into above formula as follows.

$n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}$