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vagabundo [1.1K]
2 years ago
6

An appliance draws 3 amperes at 120 V (plugged into the wall). If the same appliance is run with a 12 V car battery, how many am

peres will it need?
Physics
1 answer:
Stolb23 [73]2 years ago
3 0

The appliance is run with a 12 V car battery and the value of the electric current will be 0.3A.

<h3>What is electric current?</h3>

The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.

From ohm's law;

Case 1;

V=IR

120 V = 3 A × R

R = 40 ohm

For the same appliances, the value of the resistance is the same;

Case 2;

V=IR

12 V =  I × 40 ohm

I = 0.3 A

Hence the value of the current for case 2 will be 0.3 A.

To learn more about the electric current refer;

brainly.com/question/7643273

#SPJ1

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Sports like swimming and track are individual races but in the end everyone on the team races come together to make a team placement.
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On the ride "Spindletop" at the amusement park Six Flags Over Texas, people stood against the inner wall of a hollow vertical cy
Crazy boy [7]

Answer:

<u><em>note:</em></u>

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4 0
4 years ago
While helping an astronomy professor, you discover a binary star system in which the two stars are in circular orbits about the
svetoff [14.1K]

Answer:

The value is d =  3.66 *10^{10} \  m

Explanation:

From the question we are told that

The orbital period is T =  31.3 \ days = 31.3 * 86400 = 2704320 \ s

Generally for the centripetal force acting one of the stars will be equal to the gravitational force between the stars and this can be mathematically represented as

F_g  =  F_c

=> \frac{Gm*m}{d^2} =  \frac{mv^2}{r}

Here m represents the mass of each star given that they have same mass and this equal to the mass of the sun whose value is

m  =  1.989*10^{30} \  kg

d(2 * r) is the diameter of the orbit which is distance between each star

r is the radius of the orbit

G is the gravitational constant with value G= 6.67*0^{-11} \  m^2/kg \cdot s^2

v is the velocity of the stars which can be mathematically represented as

v  =  \frac{2 \pi r}{T}

So

\frac{Gmm }{(2 * r)^2}  = \frac{m (\frac{2\pi r}{T} )^2}{r}

=> r =[  \frac{Gm T^2}{16 \pi ^2} ]^{\frac{1}{3} }

=> r =  [\frac{6.67 *10^{-11} * (1.989 *10^{30}) * 2704320^2}{16 * (3.142)^2} ]^{\frac{1}{3} }

=> r =  1.83 *10^{10} \  m

Generally the distance between the star is

d =  2 * r

=> d =  2 * 1.83 *10^{10}

=> d =  3.66 *10^{10} \  m

3 0
3 years ago
Solve the below problems being sure to provide the correct significant figures.
morpeh [17]


Sum of the first ten digits is:
7+3+4+5+4+1+7+8+0 = 39

39, when divided by 9 give you the remainder of 3

9 x4, is 36
36 +3 equals 39
(39 = 9 x 4 + 3)

So X= 0
5 0
4 years ago
Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wave
Alisiya [41]

Answer:

similar wave amplitudes

Explanation:

When two waves travelling in the same medium have similar wave amplitudes they are less likely to interfere with each other destructively or constructively because the interference between waves occur when the amplitudes of the waves arrive a position in the medium in opposite directions hence they add up( superposition) or cancel each other out.

Hence if the waves have similar wave amplitudes the interference between the waves will be limited.

8 0
4 years ago
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